我正在尝试修改以下脚本,以指向与特定视图vw_foo
的索引关联。这可能吗?
SELECT name AS index_name,
STATS_DATE(OBJECT_ID, index_id) AS StatsUpdated
FROM sys.indexes
修改
当我说“关联”时,我指的是用于创建视图的基础表上的索引
答案 0 :(得分:1)
可能会对你有所帮助 -
SELECT
SCHEMA_NAME(o.[schema_id]) + '.' + o.name
, s.name
, statistics_update_date = STATS_DATE(o.[object_id], stats_id)
FROM sys.objects o
JOIN sys.stats s ON o.[object_id] = s.[object_id]
WHERE o.[type] = 'V' AND o.name = 'vw_foo'
DECLARE @table_name SYSNAME
SELECT @table_name = 'dbo.vw_foo'
<强> EDITED 强>
当我说“关联”时,我指的是所使用的表上的索引 通过视图
此查询返回使用指定表的视图列表+显示有关已使用索引的其他信息 -
SELECT
o.table_name
, b.view_name
, i.name
, stast_updates = STATS_DATE(i.[object_id], i.index_id)
, dm_ius.last_user_seek
, dm_ius.last_user_scan
, dm_ius.last_user_lookup
, dm_ius.last_user_update
, dm_ius.user_updates
, dm_ius.user_lookups
, dm_ius.user_scans
, dm_ius.user_seeks
FROM (
SELECT
table_name = s.name + '.' + o.name
, o.[object_id]
FROM sys.objects o
JOIN sys.schemas s ON o.[schema_id] = s.[schema_id]
WHERE o.[type] = 'U'
AND s.name + '.' + o.name = @table_name
) o
JOIN sys.indexes i ON o.[object_id] = i.[object_id]
AND i.[type] > 0
AND i.is_disabled = 0
AND i.is_hypothetical = 0
LEFT JOIN sys.dm_db_index_usage_stats dm_ius ON i.index_id = dm_ius.index_id AND dm_ius.[object_id] = i.[object_id]
OUTER APPLY (
SELECT
view_name = r.referencing_schema_name + '.' + r.referencing_entity_name
, r.referencing_id
FROM sys.dm_sql_referencing_entities (o.table_name, 'OBJECT') r
JOIN sys.objects o2 ON r.referencing_id = o2.[object_id]
WHERE o2.[type] = 'V'
) b
WHERE b.view_name IS NOT NULL
答案 1 :(得分:1)
现有答案可能正在检查sys.objects
中的名称,但从未这样做过。但是无论如何都没有必要这样做,因为OBJECT_ID()
函数可以让你以一种干净的方式获得object_id
:
SELECT name AS index_name,
STATS_DATE(OBJECT_ID, index_id) AS StatsUpdated
FROM sys.indexes
WHERE object_id = OBJECT_ID('vw_foo')