javascript简单替换引号内的所有内容

Question

令人惊讶，但我发现很难找到一个替换引号内文本的示例正则表达式。 E.g

1. john went for a 'walk'
2. john "walk" went for - 您可以了解任何订单

只会替换单词walk。

我确实找到了这个：Regular Expressions - how to replace a character within quotes但是对于我想要做的事情来说，这似乎很复杂。

Answer 1

试用JavaScript正则表达式：

/(["'])[^]*?\1/g

这匹配双引号或单引号之间的任何内容。

针对您的具体情况：

var s = "john went for a 'walk'";
s.replace(/(["'])[^]*?\1/g, "run");

// "john went for a run"

和

var s = "john \"walk\" went for";
s.replace(/(["'])[^]*?\1/g, "run");

// "john run went for"

Answer 2

怎么样

var string = "john went for a 'walk'";

var new_string = string.replace(/'([^;]*)'|"([^;]*)"/,"girl");

尝试http://jsfiddle.net/7dwCU/