Question

我需要帮助计算连续显示的连续头数。我不知道怎么能这样做。有人能告诉我这个程序最快捷，最简单的方法吗？我似乎无法弄明白，我已经考虑了一段时间。任何帮助将不胜感激。

import java.util.Scanner;
import java.util.Random;

public class test2
{
    public static void main( String[] args )
    {
            Random randomNumber = new Random();

            //declares and initializes the headCount and consecutiveHeads
            int headCount = 0;
            int consecutiveHeads = 0;

            //Ask user how many coin flips
            System.out.println( "How many coin flips?" );

            //stores the input in coinFlips
            Scanner input = new Scanner( System.in );
            int coinFlips = input.nextInt();

            //loop makes sure that program only accepts values or 1 or greater
            while (coinFlips < 1)
            {
                System.out.println("Please enter a value greater than or equal to 1.");
                coinFlips = input.nextInt();
            }

            for (int i = 0; i < coinFlips; i++)
            {
                int coinFace = randomNumber.nextInt(2);

                if (1 == coinFace)
                {
                    //Print H  for heads and increment the headCount
                    System.out.print( "H" );
                    headCount++;
                }
                else
                {
                    //print T for tails
                    System.out.print( "T" );


                }
            }


    }
}

Answer 1

我说的最简单的方法就是在if子句的Heads-side中计算连续的头，并在Tails端将其设置为零。像这样：

 [...]
 if (1 == coinFace)
 {
     //Print H  for heads and increment the headCount
     System.out.print( "H" );
     headCount++;
     consecutiveHeads++;
 }
 else
 {
      //print T for tails
      System.out.print( "T" );
      consecutiveHeads = 0;
      // if current head count is greater than previously recorded maximum count, replace old max

 }

如果您想记住最高连续计数，您可能需要为此添加变量。所以上面变成了：

 if (1 == coinFace)
 {
     //Print H  for heads and increment the headCount
     System.out.print( "H" );
     headCount++;
     consecutiveHeads++;
     if(consecutiveHeads > longestHeadStreak)
     {
          longestHeadStreak = consecutiveHeads;
     }
 }

如何计算硬币翻转的连续头部

1 个答案: