查找具有最高排名的值

时间:2013-04-13 02:03:09

标签: python

我有类别

Rank   Fruits:      Vegetable:    Years:
1      Apple        Lettuce       1900-1909      
2      Pineapple    Carrot        1900-1909
3      Orange       Potato        1900-1909
4      Banana       Beans         1900-1909
 Rank   Fruits:      Vegetable:    Years:
 1      Banana       Carrot        1910-1919      
 2      Orange       Potato        1910-1919
 3      Apple        Beans         1910-1919
 4      Pineapple    Lettuce       1910-1919

这是我上面给出的数据。我想找到什么时候水果香蕉最受欢迎(当排名最接近1时)。我还需要找到胡萝卜最受欢迎的时候。

例如我需要它来显示Carrot的结果将是1910-1919而Banana将是1910-1919。

我一直在乱搞这几个小时。我已经尝试将它们放入集合并使用键和值进行配置,但我没有做过任何工作。我真的很感激帮助。谢谢!

def getHighRank(data):
    nameSet=()
    nameList=[]
    for names in data:
        nameList.append[1]
        nameList.append[2]

这就是我到目前为止所拥有的。我尝试将水果和蔬菜装入一个清单。我正在考虑将其转换为一套,但我现在对于该做什么一无所知。

2 个答案:

答案 0 :(得分:2)

>>> d = {}
>>> with open('test.txt') as f:
        print f.read() # shows the file structure


Rank   Fruits:      Vegetable:    Years:
1      Apple        Lettuce       1900-1909      
2      Pineapple    Carrot        1900-1909
3      Orange       Potato        1900-1909
4      Banana       Beans         1900-1909
Rank   Fruits:      Vegetable:    Years:
1      Banana       Carrot        1910-1919      
2      Orange       Potato        1910-1919
3      Apple        Beans         1910-1919
4      Pineapple    Lettuce       1910-1919
>>> with open('test.txt') as f:
        for line in f:
            try:
                rank, fruit, vegetable, year = line.split()
                for k in (fruit, vegetable): # for both the fruit and veg
                    t = (rank, year) # tuple of rank and year
                    d[k] = min(d.get(k, t), t) # set it to the min (rank, year)
            except: # skip headers
                pass


>>> d['Apple'] # fast lookup
('1', '1900-1909')
>>> d['Apple'][1]
'1900-1909'
>>> d['Carrot'][1]
'1910-1919'
>>> d['Banana'][1]
'1910-1919'

答案 1 :(得分:1)

以下是您获取"Carrot"结果的方法。你应该可以从那里继续:

with open('filename') as f:
    print min(row.split() for row in f if row[:1].isdigit() 
                                       and 'Carrot' in row)[3]
# prints: 1910-1919