Eclipse抱怨递归函数调用

时间:2013-04-12 13:21:22

标签: c++ class implementation

一个简单的二叉搜索树类声明:

#include <vector>
#include <stdio.h>

// Provides various structures utilized by search algorithms.

// Represents an generalized node with integer value and a set of children.
class Node {
protected:
    std::vector<Node*> children;
    int value;
public:
    //Creates a new instance of a Node with a default value=-1.
    Node(){value = -1;}
    //Creates a new instance of a Node with a specified value.
    explicit Node(int value){this->value = value;}
    virtual ~Node(){delete children;}

    //Adds new Node with specified value to the list of child nodes. Multiple
    //children with the same value are allowed.
    //Returns added node.
    virtual Node* Insert(int value);
    //Removes first occurrence of a Node with specified value among children.
    virtual void Remove(int value);
};

// Represents a binary search tree node with at most two children.
class BTNode: public Node {
public:
    //Creates a new instance of a BTNode with a default value=-1.
    BTNode():Node(){}
    //Creates a new instance of a BTNode with a specified value.
    explicit BTNode(int value):Node(value){}

    //Adds new BTNode with specified value to the list of child nodes in an
    //ordered manner, that is right child value is >= value of this node and
    //left child value < value of this node.
    virtual BTNode* Insert(int value);
    //Removes first occurrence of a Node with specified value from the tree.
    virtual void Remove(int value);
    //Returns a node with specified value.
    virtual BTNode* Search(int value);
};

eclipse抱怨它的定义:

BTNode* BTNode::Search(int value){
    if (this->value == value) return *this;

    //Determines whether value is in left(0) or right(1) child.
    int child = this->value > value ? 0 : 1;
    if (children[child] != NULL)
        return children[child]->Search(value);

    return NULL;
}

调用children[child]->Search(value)的确切位置,并显示消息“方法搜索无法解析”。 Build运行得很好(没有任何编译错误)。有什么问题?

P.S.:尚未尝试运行代码,但是。正在努力。

1 个答案:

答案 0 :(得分:2)

SearchBTNode界面的一部分,但它不是Node界面的一部分,childrenvector的{​​{1}}因此,在Node*上拨打Search无效。如果Node *Node方法是有意义的,那么将其添加到Search会解决该问题。如果没有,那么你需要重新考虑你的设计,这可能超出了这个问题的范围。

还有一些其他问题。你有:

Node

virtual ~Node(){delete children;} 不是children,而是pointer。您需要遍历std::vector<Node*>并调用vector每个元素。在delete中你有这个:

Search

if (this->value == value) return *this; 会返回Search,因此应该是:

BTNode*