我想知道我是否可以为这样的事情编写分面查询
我的文档结构
UserID, AnswerID[] (int array)
1 , [9,10,11,56,78,99]
2 , [10,11,56,78,99]
3 , [8,10,12,56, 79,99]
4 , [9,10,11,56,78,99]
如果我只想要回答9,56的用户数,我可以写一个查询。但我有两个清单
List A - 9,10,11
ListB - 56,78,99
我想要两个列表的排列。
回答[9,56],[9,78],[9,99],[10,56],[10,78],[10,99],[11,56]的用户数量。 ..
如何编写查询以实现此类目标。
感谢任何帮助,
感谢。
答案 0 :(得分:1)
不使用列表时可以正常工作:
# Print ES Version
curl 'http://localhost:9200/'
# Delete the index `testindex`
curl -XDELETE 'http://localhost:9200/testindex'
# Create the index `testindex`
curl -XPUT 'http://localhost:9200/testindex' -d '{
"settings" : {
"index" : {
"number_of_shards" : 1,
"number_of_replicas" : 0
}
}
}'
# Wait for yellow
curl -XGET 'http://localhost:9200/_cluster/health?wait_for_status=yellow'
# Index docs
curl -XPUT http://localhost:9200/testindex/type/1 -d '{ "listA":"value1", "listB":"value2" }'
curl -XPUT http://localhost:9200/testindex/type/2 -d '{ "listA":"value1", "listB":"value3" }'
curl -XPUT http://localhost:9200/testindex/type/3 -d '{ "listA":"value1", "listB":"value2" }'
# Refresh docs
curl -XPOST 'http://localhost:9200/testindex/_refresh'
# TermFacet
curl -XPOST 'http://localhost:9200/testindex/type/_search?pretty' -d '
{
"query": { "match_all" : {} },
"facets" : {
"tag" : {
"terms" : {
"script_field" : "_source.listA + \" - \" + _source.listB"
}
}
}
}'
给出:
{
"took" : 1,
"timed_out" : false,
"_shards" : {
"total" : 1,
"successful" : 1,
"failed" : 0
},
"hits" : {
"total" : 3,
"max_score" : 1.0,
"hits" : [ {
"_index" : "testindex",
"_type" : "type",
"_id" : "1",
"_score" : 1.0, "_source" : { "listA":"value1", "listB":"value2" }
}, {
"_index" : "testindex",
"_type" : "type",
"_id" : "2",
"_score" : 1.0, "_source" : { "listA":"value1", "listB":"value3" }
}, {
"_index" : "testindex",
"_type" : "type",
"_id" : "3",
"_score" : 1.0, "_source" : { "listA":"value1", "listB":"value2" }
} ]
},
"facets" : {
"tag" : {
"_type" : "terms",
"missing" : 0,
"total" : 0,
"other" : -3,
"terms" : [ {
"term" : "value1 - value2",
"count" : 2
}, {
"term" : "value1 - value3",
"count" : 1
} ]
}
}
}
但是我不知道什么时候使用列表......我很想知道它是否可以完成......