Android注册和使用soap Web服务登录

时间:2013-04-11 07:54:41

标签: android soap

任何人都可以帮助我使用SOAP web service编写注册页面的代码。开发一个患者检查应用程序,其中第一个用户必须注册。 PLZ帮助我任何人对此有任何想法。谢谢你提前。

3 个答案:

答案 0 :(得分:0)

答案 1 :(得分:0)

您可以使用Ksoap2将数据发送到您的网络服务并记录您的用户。这里有一个关于使用这个库从webservice获取数据的初学者教程(了解基础知识)communicate between asp net webservice an android app using ksoap2

答案 2 :(得分:0)

          SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME1);        

        request.addProperty("userFirstname",sFirstName);
        request.addProperty("userLastname",sLastName);
        request.addProperty("dob",sBOD );
        request.addProperty("gender",spinnersex.getSelectedItem().toString());
        request.addProperty("address",sAddress);
        request.addProperty("city",sCity);
        request.addProperty("state", sState);
        request.addProperty("pincode",sAreaCode);
        request.addProperty("mobile",sPhoneNo );
        request.addProperty("mailid",sEmailId );
        request.addProperty("bg",spinnerBloodgroup.getSelectedItem().toString());
       // request.addProperty("date",Date.getText().toString());
        request.addProperty("weight",sweight); 

        //Declare the version of the SOAP request
        SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);     
        envelope.setOutputSoapObject(request);
        envelope.dotNet = true;
        try {

            HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);

            //this is the actual part that will call the webservice
             androidHttpTransport.call(SOAP_ACTION1, envelope);
            Log.e("ressult","data"+ re);

        SoapObject result = (SoapObject)envelope.getResponse();  
            Log.e("value of result", " result"+result);
            if(result!= null)
            {
                Toast.makeText(getApplicationContext(), "successfully register ", 2000).show()  ;
            }
            else {

                Toast.makeText(getApplicationContext(), "Try Again..", 2000).show() ;   
            }

        } catch (Exception e) {
            e.printStackTrace();
        }

        return null;
  

我认为您的问题将通过此代码解决,否则我会简要地给您   描述