我有以下从外部方收到的JSON字符串。
{
"team":[
{
"v1":"",
"attributes":{
"eighty_min_score":"",
"home_or_away":"home",
"score":"22",
"team_id":"500"
}
},
{
"v1":"",
"attributes":{
"eighty_min_score":"",
"home_or_away":"away",
"score":"30",
"team_id":"600"
}
}
]
}
我的映射类:
public class Attributes
{
public string eighty_min_score { get; set; }
public string home_or_away { get; set; }
public string score { get; set; }
public string team_id { get; set; }
}
public class Team
{
public string v1 { get; set; }
public Attributes attributes { get; set; }
}
public class RootObject
{
public List<Team> team { get; set; }
}
问题是我不喜欢Attributes
中的attributes
班级名称和Team
字段名称类。相反,我希望将其命名为TeamScore
,并从字段名称中删除_
并给出正确的名称。
JsonConvert.DeserializeObject<RootObject>(jsonText);
我可以将Attributes
重命名为TeamScore
,但如果我更改attributes
类中的字段名称Team
,则不会正确反序列化并给我null
。我怎么能克服这个?
答案 0 :(得分:508)
Json.NET有JsonPropertyAttribute
,允许您指定JSON属性的名称,因此您的代码应为:
public class TeamScore
{
[JsonProperty("eighty_min_score")]
public string EightyMinScore { get; set; }
[JsonProperty("home_or_away")]
public string HomeOrAway { get; set; }
[JsonProperty("score ")]
public string Score { get; set; }
[JsonProperty("team_id")]
public string TeamId { get; set; }
}
public class Team
{
public string v1 { get; set; }
[JsonProperty("attributes")]
public TeamScore TeamScores { get; set; }
}
public class RootObject
{
public List<Team> Team { get; set; }
}
答案 1 :(得分:94)
如果您想使用动态映射,并且不希望使用属性来混淆模型,这种方法对我有用
用法:
var settings = new JsonSerializerSettings();
settings.DateFormatString = "YYYY-MM-DD";
settings.ContractResolver = new CustomContractResolver();
this.DataContext = JsonConvert.DeserializeObject<CountResponse>(jsonString, settings);
逻辑:
public class CustomContractResolver : DefaultContractResolver
{
private Dictionary<string, string> PropertyMappings { get; set; }
public CustomContractResolver()
{
this.PropertyMappings = new Dictionary<string, string>
{
{"Meta", "meta"},
{"LastUpdated", "last_updated"},
{"Disclaimer", "disclaimer"},
{"License", "license"},
{"CountResults", "results"},
{"Term", "term"},
{"Count", "count"},
};
}
protected override string ResolvePropertyName(string propertyName)
{
string resolvedName = null;
var resolved = this.PropertyMappings.TryGetValue(propertyName, out resolvedName);
return (resolved) ? resolvedName : base.ResolvePropertyName(propertyName);
}
}
答案 2 :(得分:7)
添加到Jacks解决方案。我需要使用JsonProperty和Serialize反序列化,同时忽略JsonProperty(反之亦然)。 ReflectionHelper和Attribute Helper只是一个辅助类,它获取属性的属性或属性列表。我可以包括,如果有人真正关心。使用下面的示例,您可以序列化viewmodel并获取“Amount”,即使JsonProperty是“RecurringPrice”。
/// <summary>
/// Ignore the Json Property attribute. This is usefule when you want to serialize or deserialize differently and not
/// let the JsonProperty control everything.
/// </summary>
/// <typeparam name="T"></typeparam>
public class IgnoreJsonPropertyResolver<T> : DefaultContractResolver
{
private Dictionary<string, string> PropertyMappings { get; set; }
public IgnoreJsonPropertyResolver()
{
this.PropertyMappings = new Dictionary<string, string>();
var properties = ReflectionHelper<T>.GetGetProperties(false)();
foreach (var propertyInfo in properties)
{
var jsonProperty = AttributeHelper.GetAttribute<JsonPropertyAttribute>(propertyInfo);
if (jsonProperty != null)
{
PropertyMappings.Add(jsonProperty.PropertyName, propertyInfo.Name);
}
}
}
protected override string ResolvePropertyName(string propertyName)
{
string resolvedName = null;
var resolved = this.PropertyMappings.TryGetValue(propertyName, out resolvedName);
return (resolved) ? resolvedName : base.ResolvePropertyName(propertyName);
}
}
用法:
var settings = new JsonSerializerSettings();
settings.DateFormatString = "YYYY-MM-DD";
settings.ContractResolver = new IgnoreJsonPropertyResolver<PlanViewModel>();
var model = new PlanViewModel() {Amount = 100};
var strModel = JsonConvert.SerializeObject(model,settings);
型号:
public class PlanViewModel
{
/// <summary>
/// The customer is charged an amount over an interval for the subscription.
/// </summary>
[JsonProperty(PropertyName = "RecurringPrice")]
public double Amount { get; set; }
/// <summary>
/// Indicates the number of intervals between each billing. If interval=2, the customer would be billed every two
/// months or years depending on the value for interval_unit.
/// </summary>
public int Interval { get; set; } = 1;
/// <summary>
/// Number of free trial days that can be granted when a customer is subscribed to this plan.
/// </summary>
public int TrialPeriod { get; set; } = 30;
/// <summary>
/// This indicates a one-time fee charged upfront while creating a subscription for this plan.
/// </summary>
[JsonProperty(PropertyName = "SetupFee")]
public double SetupAmount { get; set; } = 0;
/// <summary>
/// String representing the type id, usually a lookup value, for the record.
/// </summary>
[JsonProperty(PropertyName = "TypeId")]
public string Type { get; set; }
/// <summary>
/// Billing Frequency
/// </summary>
[JsonProperty(PropertyName = "BillingFrequency")]
public string Period { get; set; }
/// <summary>
/// String representing the type id, usually a lookup value, for the record.
/// </summary>
[JsonProperty(PropertyName = "PlanUseType")]
public string Purpose { get; set; }
}
答案 3 :(得分:1)
我在序列化时使用JsonProperty属性,但是在使用此ContractResolver
反序列化时却忽略它们:
public class IgnoreJsonPropertyContractResolver: DefaultContractResolver
{
protected override IList<JsonProperty> CreateProperties(Type type, MemberSerialization memberSerialization)
{
var properties = base.CreateProperties(type, memberSerialization);
foreach (var p in properties) { p.PropertyName = p.UnderlyingName; }
return properties;
}
}
ContractResolver
只是将每个属性设置回类的属性名(从Shimmy的解决方案简化)。用法:
var airplane= JsonConvert.DeserializeObject<Airplane>(json,
new JsonSerializerSettings { ContractResolver = new IgnoreJsonPropertyContractResolver() });