我们有一个JSON对象,其中一个对象的名称中包含一个破折号。在下面。
{
"veg": [
{
"id": "3",
"name": "Vegetables",
"count": "25"
},
{
"id": "4",
"name": "Dal",
"count": "2"
},
{
"id": "5",
"name": "Rice",
"count": "8"
},
{
"id": "7",
"name": "Breads",
"count": "6"
},
{
"id": "9",
"name": "Meals",
"count": "3"
},
{
"id": "46",
"name": "Extras",
"count": "10"
}
],
"non-veg": [
{
"id": "25",
"name": "Starters",
"count": "9"
},
{
"id": "30",
"name": "Gravies",
"count": "13"
},
{
"id": "50",
"name": "Rice",
"count": "4"
}
]
}
我们如何反序化这个json?
答案 0 :(得分:62)
要回答有关如何使用NewtonSoft执行此操作的问题,您将使用JsonProperty属性标志。
[JsonProperty(PropertyName="non-veg")]
public string nonVeg { get; set; }
答案 1 :(得分:19)
您可以使用DataContractJsonSerializer
来实现此目的[DataContract]
public class Item
{
[DataMember(Name = "id")]
public int Id { get; set; }
[DataMember(Name = "name")]
public string Name { get; set; }
[DataMember(Name = "count")]
public int Count { get; set; }
}
[DataContract]
public class ItemCollection
{
[DataMember(Name = "veg")]
public IEnumerable<Item> Vegetables { get; set; }
[DataMember(Name = "non-veg")]
public IEnumerable<Item> NonVegetables { get; set; }
}
现在您可以使用以下内容对其进行反序列化:
string data;
// fill the json in data variable
ItemCollection collection;
using (MemoryStream ms = new MemoryStream(Encoding.Unicode.GetBytes(data)))
{
DataContractJsonSerializer serializer = new DataContractJsonSerializer(typeof(ItemCollection));
collection = (ItemCollection)serializer.ReadObject(ms);
}