Question

嗨，这是我的问题。

编写一个使用do-while语句的程序。它读取整数 n来自键盘。如果n不在1到10的范围内，则会发出声音 “嘟嘟”并要求另一个整数。如果n在正确的范围内，则写入输出“你有输入n”然后退出。

这是我的答案。

#include <iostream>
#include <Windows.h>
using namespace std;

void main()
{
    int number = 0;
    do
    {
      cout << "Enter an integer." << endl;
      cin >> number;
      if (!(number >= 1 && number <= 10))
      {
        Beep(400, 400);
      }
    }
    while (!(number >= 1 && number <= 10));
    cout << "You have input " << number << endl;
    system("PAUSE");
}

你可以看到

行

(!(number >= 1 && number <= 10))

重复。有没有解决方法呢？

Answer 1

int GetNumber()
{
    int number;
    cout << "Enter an integer." << endl;
    cin >> number;
    return number;
}

void main()
{
    int n = GetNumber();

    while(n < 1 || n > 10)
    {
        Beep(400, 400);
        n = GetNumber();
    }

    cout << "You have input " << n << endl;
    system("PAUSE");
}

Answer 2

#include <iostream>
#include <Windows.h>
using namespace std;

void main()
{
    int number = 0;
    bool invalid_input = true;
    do
    {
      cout << "Enter an integer." << endl;
      cin >> number;
      invalid_input = !(number >= 1 && number <= 10); 
      if (invalid_input)
      {
        Beep(400, 400);
      }
    }
    while (invalid_input);
    cout << "You have input " << number << endl;
    system("PAUSE");
}

Answer 3

...也许

int number = 0;
while (true)
{
  cout << "Enter an integer." << endl;
  if (cin >> number && number >= 1 && number <= 10)
      break;
  Beep(400, 400);
}
cout << "You have input " << number << endl;
system("PAUSE");

通过删除重复代码使我的操作循环整理

3 个答案: