我想让用户再次输入一个输入，如果他拼错了＃34;我很伤心＆＃34;并完成整个转换过程。
当我输入＆＃34; imsed＆＃34;它说＆＃34;我不明白＆＃34;因为它应该并要求另一个输入，但是当我输入另一个输入时，它就会结束。
我还不能使用数组。
do {
if (a.contains("sad")) {
System.out.println("bot: " + "Hey there! Dont be sad, Here is a pun to cheer you up");
System.out.println();
i = 1 + dice.nextInt(3);
switch (i) { // start of switch
case 1:
System.out.println("Why did the traffic light felt embarrased?\n"
+ "Because everyone saw it changing");
a = input.nextLine();
break;
case 2:
System.out.println("Why was Cinderella thrown off the basketball team?"
+ "\nShe ran away from the ball.");
a = input.nextLine();
break;
case 3:
System.out.println("Why is Peter Pan always flying?\n"
+ "He neverlands.");
a = input.nextLine();
break;
} //end of switch
} else if (a.contains("again")) {
e = 1 + dice.nextInt(3);
switch (e) { // start of switch
case 1:
System.out.println("How do you know it's an emotional wedding?\n" + "When the cake is in tiers");
a = input.nextLine();
break;
case 2:
System.out.println("What does a house wear?" + "\nA Dress.");
a = input.nextLine();
break;
case 3:
System.out.println("How do you know a frenchmen plays video games?\n" + "He says wii when you ask him.");
a = input.nextLine();
break;
} //end of switch
}
} while (a.equals("again")
if (a.contains("im happy")) {
System.out.println("bot: " + "Have a great day ahead!");
}
if (!a.equals("im sad")
|| !a.equals("im happy"
|| !a.equals("again")) {
System.out.println("bot: " + "I don't understand");
a = input.nextLine();
}