如何在'where'子句中多次使用选择数据

时间：2009-10-19 02:35:20

标签： sql sql-server sql-server-2005 tsql

我在SQL 2005 DB中有两列数据

Datetime                Value
'2009-10-29 10:00:00' ' 10.1'
'2009-10-29 10:15:00' ' 10.2'
'2009-10-29 10:30:00' ' 10.3'
'2009-10-29 10:45:00' ' 10.4'

我想

SELECT Value
FROM [table]
WHERE Datetime >= '2009-10-29 10:00:00'
AND (Datetime NOT BETWEEN '2009-10-29 10:14:00' AND '2009-10-29 10:16:00' )
AND Datetime < '2009-10-29 10:35:00'

我原本希望得到

10.1
10.3

但事实并非如此......帮助？

好的，这是我正在使用的实际sql语句; 

Declare @Tagname varchar(25)
Set @Tagname = '52_RTU_#RE1002'

SELECT  DateTIme,(Runtime.dbo.v_AnalogHistory.Value), @Tagname As Tagname,0
FROM Runtime.dbo.AnalogTag INNER JOIN Runtime.dbo.v_AnalogHistory ON Runtime.dbo.AnalogTag.TagName = Runtime.dbo.v_AnalogHistory.TagName
WHERE(Runtime.dbo.v_AnalogHistory.TagName IN (@Tagname)) 
AND(Runtime.dbo.v_AnalogHistory.wwVersion = 'Latest') 
AND(Runtime.dbo.v_AnalogHistory.wwRetrievalMode = 'Full') 
AND Datetime >= '2009-08-01 00:00:00' 
AND (Datetime NOT BETWEEN '2009-08-01 10:27:00' AND '2009-08-01 11:30:00')
AND Datetime < '2009-08-01 11:35:00'

这是没有应用NOT BETWEEN语句的数据集： 

2009-08-01 00:00:00.000 0.72    52_RTU_#RE1002
2009-08-01 10:25:15.300 0.44    52_RTU_#RE1002
2009-08-01 10:27:22.350 0.5 52_RTU_#RE1002
2009-08-01 10:27:25.350 0.56    52_RTU_#RE1002
2009-08-01 10:27:27.360 0.62    52_RTU_#RE1002
2009-08-01 10:27:28.760 0.68    52_RTU_#RE1002
2009-08-01 10:27:30.360 0.74    52_RTU_#RE1002
2009-08-01 10:27:31.560 0.8 52_RTU_#RE1002
2009-08-01 10:27:32.760 0.87    52_RTU_#RE1002
2009-08-01 10:27:33.960 0.94    52_RTU_#RE1002
2009-08-01 10:27:35.370 1   52_RTU_#RE1002
2009-08-01 10:27:36.360 1.05999992370605    52_RTU_#RE1002
2009-08-01 10:27:37.570 1.13    52_RTU_#RE1002
2009-08-01 10:27:38.760 1.19000007629395    52_RTU_#RE1002
2009-08-01 10:27:40.360 1.25    52_RTU_#RE1002
2009-08-01 10:27:41.760 1.31    52_RTU_#RE1002
2009-08-01 10:27:43.560 1.37    52_RTU_#RE1002
2009-08-01 10:27:46.360 1.43    52_RTU_#RE1002
2009-08-01 10:27:57.580 1.37    52_RTU_#RE1002
2009-08-01 10:28:00.380 1.31    52_RTU_#RE1002
2009-08-01 10:28:02.580 1.25    52_RTU_#RE1002
2009-08-01 10:28:04.980 1.19000007629395    52_RTU_#RE1002
2009-08-01 10:28:07.390 1.13    52_RTU_#RE1002
2009-08-01 10:28:09.590 1.07000007629395    52_RTU_#RE1002
2009-08-01 10:28:11.810 1.01    52_RTU_#RE1002
2009-08-01 10:28:14.480 0.95    52_RTU_#RE1002
2009-08-01 10:28:16.630 0.89    52_RTU_#RE1002
2009-08-01 10:28:19.430 0.83    52_RTU_#RE1002
2009-08-01 10:28:21.830 0.77    52_RTU_#RE1002
2009-08-01 10:28:24.850 0.71    52_RTU_#RE1002
2009-08-01 10:28:28.240 0.65    52_RTU_#RE1002
2009-08-01 10:28:31.450 0.589999961853027   52_RTU_#RE1002
2009-08-01 10:28:35.250 0.529999961853027   52_RTU_#RE1002
2009-08-01 10:28:39.460 0.47    52_RTU_#RE1002
2009-08-01 10:28:44.470 0.41    52_RTU_#RE1002
2009-08-01 10:28:49.860 0.35    52_RTU_#RE1002
2009-08-01 10:28:56.870 0.29    52_RTU_#RE1002
2009-08-01 10:29:05.880 0.23    52_RTU_#RE1002
2009-08-01 10:29:17.890 0.17    52_RTU_#RE1002
2009-08-01 10:29:32.320 0.11    52_RTU_#RE1002
2009-08-01 10:29:57.930 0.05    52_RTU_#RE1002
2009-08-01 10:32:46.360 0.01    52_RTU_#RE1002
2009-08-01 10:37:46.360 0.01    52_RTU_#RE1002
2009-08-01 10:42:46.260 0.01    52_RTU_#RE1002
2009-08-01 10:47:46.310 0.01    52_RTU_#RE1002
2009-08-01 10:52:46.360 0.01    52_RTU_#RE1002
2009-08-01 10:57:46.230 0.01    52_RTU_#RE1002
2009-08-01 11:02:46.300 0.01    52_RTU_#RE1002
2009-08-01 11:07:47.230 0.01    52_RTU_#RE1002
2009-08-01 11:12:47.370 0.03    52_RTU_#RE1002
2009-08-01 11:17:47.260 0.04    52_RTU_#RE1002
2009-08-01 11:22:12.490 0.11    52_RTU_#RE1002
2009-08-01 11:22:47.300 0.14    52_RTU_#RE1002
2009-08-01 11:27:47.360 0.14    52_RTU_#RE1002
2009-08-01 11:28:40.610 0.17    52_RTU_#RE1002
2009-08-01 11:32:48.330 0.13    52_RTU_#RE1002
2009-08-01 11:34:34.680 0.23    52_RTU_#RE1002

以下是未经过BETWEEN应用的数据

2009-08-01 11:32:48.330 0.13    52_RTU_#RE1002  0
2009-08-01 11:34:34.680 0.23    52_RTU_#RE1002  0

5 个答案:

答案 0 :(得分：1)

使用：

SELECT t.value
  FROM TABLE t
 WHERE t.datetime BETWEEN '2009-10-29 10:00:00' AND '2009-10-29 10:13:59'
UNION ALL
SELECT t.value
  FROM TABLE t
 WHERE t.datetime BETWEEN '2009-10-29 10:16:01' AND '2009-10-29 10:34:59'

...现在尝试：

SELECT t.value
  FROM TABLE t
 WHERE (t.datetime BETWEEN '2009-10-29 10:00:00' AND '2009-10-29 10:13:59'
        OR t.datetime BETWEEN '2009-10-29 10:16:01' AND '2009-10-29 10:34:59')

答案 1 :(得分：0)

您可以尝试这样的事情：

SELECT Value
FROM [table]
WHERE (Datetime >= '2009-10-29 10:00:00' AND Datetime < '2009-10-29 10:14:00')
OR (Datetime > '2009-10-29 10:16:00' AND Datetime < '2009-10-29 10:35:00')

答案 2 :(得分：0)

那些实际的日期时间列是某种形式的varchar吗？我问，因为DB2中的类似查询工作正常：

drop table xx; commit;                                
create table xx (val1 integer, val2 integer); commit;                                
insert into xx values (1000,101);
insert into xx values (1015,102);
insert into xx values (1030,103);
insert into xx values (1045,104);
commit;
select * from xx
where val1 >= 1000
and (val1 not between 1014 and 1029)   
and val1 < 1035;

返回：

VAL1  VAL2              
1000   101              
1030   103              
DSNE610I NUMBER OF ROWS DISPLAYED IS 2

事实上，即使有时间戳，我也能得到正确的结果：

drop table drlan.xx;                                       
commit;                                                    
create table drlan.xx (                                    
  val1 timestamp,                                          
  val2 varchar(4)                                          
);                                                         
commit;                                                    
insert into drlan.xx values ('2009-10-29 10:00:00','10.1');
insert into drlan.xx values ('2009-10-29 10:15:00','10.2');
insert into drlan.xx values ('2009-10-29 10:30:00','10.3');
insert into drlan.xx values ('2009-10-29 10:45:00','10.4');
commit;                                                    
select * from drlan.xx                                     
where val1 >= '2009-10-29 10:00:00'                        
and (val1 not between '2009-10-29 10:14:00'                
                  and '2009-10-29 10:16:00')               
and val1 < '2009-10-29 10:35:00';                          

VAL1                        VAL2              
2009-10-29-10.00.00.000000  10.1      
2009-10-29-10.30.00.000000  10.3      
DSNE610I NUMBER OF ROWS DISPLAYED IS 2

这让我相信SQL Server存在某种问题。

答案 3 :(得分：0)

以下适用于SQL Server 2005。

create table xx (val1 datetime, val2 varchar(10)); 

insert into xx values ('2009-10-29 10:00:00', ' 10.1');
insert into xx values ('2009-10-29 10:15:00', ' 10.2');
insert into xx values ('2009-10-29 10:30:00', ' 10.3');
insert into xx values ('2009-10-29 10:45:00', ' 10.4');


SELECT val2
FROM [xx]
WHERE val1 >= '2009-10-29 10:00:00'
AND (val1 NOT BETWEEN '2009-10-29 10:14:00' AND '2009-10-29 10:16:00' )
AND val1 < '2009-10-29 10:35:00'

但如果你执行

insert into xx values ('2009-10-29 9:59:59.999', ' 10.8');

然后在SQL Server Management Studio中显示为

2009-10-29 10:00:00.000  10.8

您确定未接受的值吗？

答案 4 :(得分：0)

好的，因为事实证明存储/检索引擎（一种名为INsql的产品）sql从中获取数据似乎不适用于在statment事物中的多次。如果我选择整个数据集到一个临时表并使用sql在那里工作，NOT BETWEEN语句工作正常。谢谢大家的帮助，缩小范围！

相关问题
最新问题