Question

我正在尝试增强我在商家网站中发现的SQL错误。

我有两张桌子：

------ Table "products" ------
| id_product | product_name |
-----------------------------
|          1 |      T-shirt |
|          2 |     Trousers |
|          3 |  Sweat-shirt |
|          4 |        Socks |

----------- Table "features" -----------
| id_product | feature | feature_value |
----------------------------------------
|          1 |   Color |           Red |
|          1 |    Size |             M |
|          1 |  Fabric |        Cotton |
|          2 |   Color |          Blue |
|          2 |    Size |             S |
|          2 |  Fabric |     Polyester |
|          3 |   Color |           Red |
|          3 |    Size |             L |
|          3 |  Fabric |          Wool |
|          4 |   Color |         White |
|          4 |    Size |             L |
|          4 |  Fabric |        Cotton |

我正在尝试检索具有以下功能的产品：

其中颜色为红色或蓝色
其中大小为M
织物是棉花

我的查询如下：

SELECT p.id_product
FROM products p
WHERE p.id_product IN (SELECT f.id_product FROM features f WHERE f.feature_value IN ("Red", "Blue"))
    AND p.id_product IN (SELECT f.id_product FROM features f WHERE f.feature_value = "M")
    AND p.id_product IN (SELECT f.id_product FROM features f WHERE f.feature_value = "Cotton")
GROUP BY p.id_product

（当然，实际上，我的表格和我的查询比这更复杂，我只关注有问题的部分）

如果选择了8个或更多功能，WHERE子句中的多个SELECT会导致整个服务器速度变慢。有没有办法避免在WHERE子句中进行这么多查询？

编辑：例如，这是一个真实的查询：

SELECT p.id_product id_product
FROM ps_product p 
INNER JOIN ps_category_product cp ON p.id_product = cp.id_product 
INNER JOIN ps_category c ON (c.id_category = cp.id_category AND c.nleft >= 6 AND c.nright <= 7 AND c.active = 1)
LEFT JOIN ps_stock_available sa ON (sa.id_product = p.id_product AND sa.id_shop = 1) 
INNER JOIN ps_product_shop product_shop ON (product_shop.id_product = p.id_product AND product_shop.id_shop = 1)
WHERE 1
AND product_shop.active = 1
AND product_shop.visibility IN ("both", "catalog")
AND p.id_manufacturer IN (5,4)
AND sa.quantity > 0
AND p.id_product IN (SELECT id_product FROM ps_feature_product fp WHERE fp.id_feature_value = 82)
AND p.id_product IN (SELECT id_product FROM ps_feature_product fp WHERE fp.id_feature_value = 37248)
AND p.id_product IN (SELECT id_product FROM ps_feature_product fp WHERE fp.id_feature_value = 181)
AND p.id_product IN (SELECT id_product FROM ps_feature_product fp WHERE fp.id_feature_value = 37821)
AND p.id_product IN (SELECT id_product FROM ps_feature_product fp WHERE fp.id_feature_value = 33907)
AND p.id_product IN (SELECT id_product FROM ps_feature_product fp WHERE fp.id_feature_value = 33902)
AND p.id_product IN (SELECT id_product FROM ps_feature_product fp WHERE fp.id_feature_value = 70)
AND p.id_product IN (SELECT id_product FROM ps_feature_product fp WHERE fp.id_feature_value = 76)
AND p.id_product IN (SELECT id_product FROM ps_feature_product fp WHERE fp.id_feature_value = 291)
AND p.id_product IN (SELECT id_product FROM ps_feature_product fp WHERE fp.id_feature_value = 75)
AND p.id_product IN (SELECT id_product FROM ps_feature_product fp WHERE fp.id_feature_value = 44459)
GROUP BY id_product

Answer 1

您可以使用JOIN和HAVING子句：

SELECT p.id_product
FROM products p
JOIN features f
  ON p.id_product = f.id_product
GROUP BY p.id_product
HAVING COUNT(CASE WHEN f.feature_value IN ('Red', 'Blue') THEN 1 END) > 0
   AND COUNT(CASE WHEN f.feature_value = 'M' THEN 1 END) > 0
   AND COUNT(CASE WHEN f.feature_value = 'Cotton' THEN 1 END) > 0;

的 LiveDemo

甚至更短（MySQL）：

HAVING SUM(f.feature_value IN ('Red', 'Blue')) > 0 AND SUM(f.feature_value = 'M') > 0 AND SUM(f.feature_value = 'Cotton') > 0;

Answer 2

SELECT
  P.id_product
FROM
  products P
  INNER JOIN features F
    ON P.id_product = F.id_product
WHERE
    (F.featurure = 'Color' AND F.feature_value IN ('red', 'blue'))
    OR (F.featurure = 'Size' AND F.feature_value IN ('M'))
    OR (F.featurure = 'Fabric' AND F.feature_value IN ('Cotton'))
GROUP BY
    P.id_product
HAVING
    COUNT(DISTINCT F.feature) = 3

HAVING条件告诉我们，应该至少有3种不同的匹配功能（这是你搜索字段的数量）。

Answer 3

试试这个，希望它会有所帮助。

SELECT p.id_product,count(f.feature_value)
FROM products p, features f
where f.id_product=p.id_product 
and f.feature_value in ("Red","Blue") 
or f.feature_value = "M"
or f.feature_value = "Cotton"
group by p.id_product

避免在WHERE子句中使用多个SELECT

3 个答案: