Question

如何删除从api返回的嵌套json对象，如下所示，并通过使用jquery以通用方式取消对象，将其显示为单个字段。这是我的json对象

 "response": {
"content": 
"[ {    
      "Id": 0,    
     "Name": "Some name",    
     "createdOnDate": "0001-01-01T00:00:00",      
    "keyValueList": 
      [      
           {        
             "Key": "key1",        
            "Value": "Sample Data key 1"      
            },      
           {        
            "Key": "key2",        
           "Value": "sample data key 2   
      ] }]"

这是在取消之后应该如何。

[{
    "Id": 123,
        "Name": "some name",
        "createdOnDate": "2013-01-22T17:02:00",
        "key1": "this is my key1",
        "key2": "this is my key2"

}]

Answer 1

这是无效的JSON。确保您之前有效。之后，您可以遍历属性并按照您想要的方式设置它们。

$.each(content[0]['keyValueList'], function (k, value) {
    content[0][value['Key']] = value['Value']
});

delete content[0]['keyValueList'];

http://jsfiddle.net/TjQzv/3/

Unnest从api返回的JSon对象

1 个答案: