我不明白为什么这个GROUP_CONCAT不起作用,就外部查询而言,返回了3行所以我想通过它来组合group_concat但是它不喜欢它...
http://sqlfiddle.com/#!2/24764/3
CREATE TABLE nested_category (
category_id INT AUTO_INCREMENT PRIMARY KEY,
name VARCHAR(20) NOT NULL,
lft INT NOT NULL,
rgt INT NOT NULL
);
INSERT INTO nested_category VALUES(1,'ELECTRONICS',1,20),(2,'TELEVISIONS',2,9),(3,'TUBE',3,4),
(4,'LCD',5,6),(5,'PLASMA',7,8),(6,'PORTABLE ELECTRONICS',10,19),(7,'MP3 PLAYERS',11,14),(8,'FLASH',12,13),
(9,'CD PLAYERS',15,16),(10,'2 WAY RADIOS',17,18);
SELECT GROUP_CONCAT(rs.category_id, ',')
FROM
(
SELECT node.category_id, node.name, (COUNT(parent.name) - (sub_tree.depth + 1)) AS depth
FROM nested_category AS node,
nested_category AS parent,
nested_category AS sub_parent,
(
SELECT node.category_id, node.name, (COUNT(parent.name) - 1) AS depth
FROM nested_category AS node,
nested_category AS parent
WHERE node.lft BETWEEN parent.lft AND parent.rgt
AND node.name = 'PORTABLE ELECTRONICS'
GROUP BY node.name
ORDER BY node.lft
)AS sub_tree
WHERE node.lft BETWEEN parent.lft AND parent.rgt
AND node.lft BETWEEN sub_parent.lft AND sub_parent.rgt
AND sub_parent.name = sub_tree.name
GROUP BY node.name
HAVING depth = 1
ORDER BY node.lft
) as rs
GROUP BY rs.category_id
答案 0 :(得分:9)
两件事:
首先:将GROUP_CONCAT(rs.category_id, ',')
更改为GROUP_CONCAT(rs.category_id)
逗号是默认分隔符,from the docs您可以看到,如果您想要更改分隔符,就像
GROUP_CONCAT(rs.category_id SEPARATOR '|')
第二:删除最后一个:
GROUP BY rs.category_id
如果您group by
每个category_id
,则表示每个category_id
都在其自己的集合中,因此group_concat
每行只有一个类别。
答案 1 :(得分:1)
尝试此查询
SELECT GROUP_CONCAT(rs.category_id)
FROM
(
SELECT node.category_id, node.name, (COUNT(parent.name) - (sub_tree.depth + 1)) AS depth
FROM nested_category AS node,
nested_category AS parent,
nested_category AS sub_parent,
(
SELECT node.category_id, node.name, (COUNT(parent.name) - 1) AS depth
FROM nested_category AS node,
nested_category AS parent
WHERE node.lft BETWEEN parent.lft AND parent.rgt
AND node.name = 'PORTABLE ELECTRONICS'
GROUP BY node.name
ORDER BY node.lft
)AS sub_tree
WHERE node.lft BETWEEN parent.lft AND parent.rgt
AND node.lft BETWEEN sub_parent.lft AND sub_parent.rgt
AND sub_parent.name = sub_tree.name
GROUP BY node.name
HAVING depth = 1
ORDER BY node.lft
) as rs
<强>输出强>
| GROUP_CONCAT(RS.CATEGORY_ID) |
--------------------------------
| 7,9,10 |