Question

我的程序所做的是首先打印当前时间，然后用户按下回车键。然后再打印出时间并计算用户等待输入的时间。

我无法抽出时间来减去。我从stackoverflow中的另一个问题中获取了打印本地时间的代码。

#include <iostream>
#include <ctime>
using namespace std;

void main()
{
    time_t rawtime;
    struct tm * timeinfo;

    time ( &rawtime );
    timeinfo = localtime ( &rawtime );
    printf ( "Current local time and date: %s", asctime (timeinfo) );

    cout << "Press enter" << endl;
    cin.ignore();

    time_t rawtime2;
    struct tm * timeinfo2;

    time ( &rawtime2 );
    timeinfo2 = localtime ( &rawtime2 );
    printf ( "Later local time and date: %s", asctime (timeinfo2) );

    printf ( "You took %s", ( asctime (timeinfo2) - asctime (timeinfo) ) ); //math won't work here
    printf ( " seconds to press enter. ");
    cout << endl;
}

Answer 1

cout << "Elapsed time: " << rawtime2 - rawtime << " seconds" << endl;

Answer 2

printf ( "You took %s", ( asctime (timeinfo2) - asctime (timeinfo) ) ); //math won't work here

没有。在这种情况下，两个char*之间的差异没有任何意义。你真的只需要采用已经在整数秒内的rawtime和rawtime2，的差异。

此外，您不应在c++代码中混用printf()和std::cout，因为它不是惯用的，并且使代码更难阅读。因此，也许这样的事情会更好......

#include <ctime>
#include <iostream>

int main()
{
    time_t rawtime;
    struct tm* timeinfo;

    time(&rawtime);
    timeinfo = localtime(&rawtime);
    std::cout << "Current local time and date: " << asctime(timeinfo);
    std::cout << "Press enter\n";

    std::cin.ignore();

    time_t rawtime2;
    struct tm* timeinfo2;

    time(&rawtime2);
    timeinfo2 = localtime(&rawtime2);
    std::cout << "Later local time and date: " << asctime(timeinfo2);

    time_t const timediff = rawtime2 - rawtime;
    std::cout << "You took " << timediff << " seconds to press enter.\n";
}

注意：

main() should return int, not void

Answer 3

这是一个稍微清洁的解决方案，主要区别在于使用int main（）并返回0;最后，main应该永远不会返回void，这是一个糟糕的编程习惯。

#include <iostream>
#include <ctime>
using namespace std;

int main()
{
    time_t rawtime;
    struct tm * timeinfo;

    time ( &rawtime );
    timeinfo = localtime ( &rawtime );
    cout <<  "Current local time and date:  " <<  asctime (timeinfo) ;

    cout << "Press enter" << endl;
    cin.ignore();

    time_t rawtime2;
    struct tm * timeinfo2;

    time ( &rawtime2 );
    timeinfo2 = localtime ( &rawtime2 );
    cout <<  "Later local time and date:   " <<  asctime (timeinfo2) << endl;

    int prinAll = rawtime2 - rawtime;

    cout <<  "You took "  << prinAll << " seconds to press enter" << endl; //math     won't work here

    cout << endl;

    return 0;
}

试图计算两次之间的差异，不会减去

3 个答案:

注意：