我有两个字符串变量,如StartTime和EndTime。我需要通过用StartTime减去EndTime来计算TotalTime。
StartTime和EndTime的格式如下:
StartTime = "08:00 AM";
EndTime = "04:00 PM";
小时和分钟格式的总时间。如何在Android中计算?
答案 0 :(得分:37)
尝试以下代码。
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("HH:mm a");
date1 = simpleDateFormat.parse("08:00 AM");
date2 = simpleDateFormat.parse("04:00 PM");
long difference = date2.getTime() - date1.getTime();
days = (int) (difference / (1000*60*60*24));
hours = (int) ((difference - (1000*60*60*24*days)) / (1000*60*60));
min = (int) (difference - (1000*60*60*24*days) - (1000*60*60*hours)) / (1000*60);
hours = (hours < 0 ? -hours : hours);
Log.i("======= Hours"," :: "+hours);
输出 - 小时数:8
答案 1 :(得分:3)
看一下DateFormat,你可以使用它来解析你的字符串,使用parse(String source)方法,你就可以轻松地操纵两个Dates对象来获得你想要的东西。
DateFormat df = DateFormat.getInstance();
Date date1 = df.parse(string1);
Date date2 = df.parse(string2);
long difference = date1.getTime() - date2.getTime();
days = (int) (difference / (1000*60*60*24));
hours = (int) ((difference - (1000*60*60*24*days)) / (1000*60*60));
min = (int) (difference - (1000*60*60*24*days) - (1000*60*60*hours)) / (1000*60);
String diffHours = df.format(hours);
日期差异
Date myDate = new Date(difference);
显示日期:
String diff = df.format(myDate);
答案 2 :(得分:3)
注意:更正了Chirag Raval提供的代码,因为在我们尝试从22:00到07:00找时间时,Chirag提供的代码存在一些问题。
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("HH:mm");
Date startDate = simpleDateFormat.parse("22:00");
Date endDate = simpleDateFormat.parse("07:00");
long difference = endDate.getTime() - startDate.getTime();
if(difference<0)
{
Date dateMax = simpleDateFormat.parse("24:00");
Date dateMin = simpleDateFormat.parse("00:00");
difference=(dateMax.getTime() -startDate.getTime() )+(endDate.getTime()-dateMin.getTime());
}
int days = (int) (difference / (1000*60*60*24));
int hours = (int) ((difference - (1000*60*60*24*days)) / (1000*60*60));
int min = (int) (difference - (1000*60*60*24*days) - (1000*60*60*hours)) / (1000*60);
Log.i("log_tag","Hours: "+hours+", Mins: "+min);
结果将是:小时:9,分钟:0
答案 3 :(得分:1)
我想贡献现代的答案。
DateTimeFormatter timeFormatter = DateTimeFormatter.ofPattern("hh:mm a", Locale.ENGLISH);
String startTime = "08:00 AM";
String endTime = "04:00 PM";
LocalTime start = LocalTime.parse(startTime, timeFormatter);
LocalTime end = LocalTime.parse(endTime, timeFormatter);
Duration diff = Duration.between(start, end);
long hours = diff.toHours();
long minutes = diff.minusHours(hours).toMinutes();
String totalTimeString = String.format("%02d:%02d", hours, minutes);
System.out.println("TotalTime in Hours and Mins Format is " + totalTimeString);
此代码段的输出为:
小时和分钟格式的总时间为08:00
(在具有ThreeTen Backport的Java 1.7.0_67上进行了测试。)
在其他答案(SimpleDateFormat
,Date
,DateFormat
和Calendar
中使用的日期时间类都已经过时且设计不良。可能更糟的是,一个答案是在没有任何库类帮助的情况下“手动”解析和计算。这很复杂且容易出错,从不建议这样做。相反,我使用的是java.time,这是现代的Java日期和时间API。与之合作真是太好了。
是的,java.time在较新和较旧的Android设备上均可正常运行。它只需要至少 Java 6 。
org.threeten.bp
导入日期和时间类别,并带有以下子包:org.threeten.bp.Duration
,org.threeten.bp.LocalTime
和org.threeten.bp.format.DateTimeFormatter
。java.time
。java.time
向Java 6和7(JSR-310的ThreeTen)的反向端口。答案 4 :(得分:0)
请试试这个......
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("HH:mm");
try {
date1 = simpleDateFormat.parse("08:00 AM");
} catch (ParseException e) {
e.printStackTrace();
}
try {
date2 = simpleDateFormat.parse("04:00 PM");
} catch (ParseException e) {
e.printStackTrace();
}
long difference = date2.getTime() - date1.getTime();
int days = (int) (difference / (1000 * 60 * 60 * 24));
int hours = (int) ((difference - (1000 * 60 * 60 * 24 * days)) / (1000 * 60 * 60));
int min = (int) (difference - (1000 * 60 * 60 * 24 * days) - (1000 * 60 * 60 * hours))
/ (1000 * 60);
hours = (hours < 0 ? -hours : hours);
Log.i("======= Hours", " :: " + hours);
答案 5 :(得分:0)
Try simple piece of code using For 24 hour time
StartTime = "10:00";
EndTime = "13:00";
here starthour=10 and end hour=13
if(TextUtils.isEmpty(txtDate.getText().toString())||TextUtils.isEmpty(txtDate1.getText().toString())||TextUtils.isEmpty(txtTime.getText().toString())||TextUtils.isEmpty(txtTime1.getText().toString()))
{
Toast.makeText(getApplicationContext(), "Date/Time fields cannot be blank", Toast.LENGTH_SHORT).show();
}
else {
if (starthour > endhour) {
Toast.makeText(getApplicationContext(), "Start Time Should Be Less Than End Time", Toast.LENGTH_SHORT).show();
} else if (starthour == endhour) {
if (startmin > endmin) {
Toast.makeText(getApplicationContext(), "Start Time Should Be Less Than End Time", Toast.LENGTH_SHORT).show();
}
else{
tvalid = "True";
}
} else {
// Toast.makeText(getApplicationContext(),"Sucess"+(endhour-starthour)+(endmin-startmin),Toast.LENGTH_SHORT).show();
tvalid = "True";
}
}
same for date also
答案 6 :(得分:0)
String mStrDifferenceTime =compareTwoTimeAMPM("11:06 PM","05:07 AM");
Log.e("App---Time ", mStrDifferenceTime+" Minutes");
public static String getCurrentDateUsingCalendar() {
Date mDate = new Date(); // to get the date
@SuppressLint("SimpleDateFormat") SimpleDateFormat mSimpleDateFormat = new SimpleDateFormat("dd-MM-yyyy"); // getting date in this format
return mSimpleDateFormat.format(mDate.getTime());
}
public static String getNextDateUsingCalendar() {
Calendar mCalendar = Calendar.getInstance();
mCalendar.add(Calendar.DAY_OF_YEAR, 1);
Date mStrTomorrow = mCalendar.getTime();
@SuppressLint("SimpleDateFormat") DateFormat mDateFormat = new SimpleDateFormat("dd-MM-yyyy");
return mDateFormat.format(mStrTomorrow);
}
public static String compareTwoTimeAMPM(String mStrStartTime, String mStrEndTime) {
String mStrCompareStartTime[] = mStrStartTime.split(" ");
String mStrCompareEndTime[] = mStrEndTime.split(" ");
int mIStartTime = Integer.parseInt(mStrCompareStartTime[0].replace(":", ""));
int mIEndTime = Integer.parseInt(mStrCompareEndTime[0].replace(":", ""));
String mStrToday = "";
String mStrTomorrow = "";
if (mIStartTime < mIEndTime && mStrCompareStartTime[1].equals("PM") && mStrCompareEndTime[1].equals("PM")) {
mStrToday = getCurrentDateUsingCalendar();
mStrTomorrow = getCurrentDateUsingCalendar();
} else if (mIStartTime < mIEndTime && mStrCompareStartTime[1].equals("AM") && mStrCompareEndTime[1].equals("AM")) {
mStrToday = getCurrentDateUsingCalendar();
mStrTomorrow = getCurrentDateUsingCalendar();
} else if (mIStartTime > mIEndTime && mStrCompareStartTime[1].equals("PM") && mStrCompareEndTime[1].equals("PM")) {
String mStrTime12[] = mStrCompareStartTime[0].split(":");
if (mStrTime12[0].equals("12")) {
mStrToday = getNextDateUsingCalendar();
mStrTomorrow = getNextDateUsingCalendar();
} else {
mStrToday = getCurrentDateUsingCalendar();
mStrTomorrow = getNextDateUsingCalendar();
}
} else if (mIStartTime > mIEndTime && mStrCompareStartTime[1].equals("AM") && mStrCompareEndTime[1].equals("AM")) {
String mStrTime12[] = mStrCompareStartTime[0].split(":");
if (mStrTime12[0].equals("12")) {
mStrToday = getNextDateUsingCalendar();
mStrTomorrow = getNextDateUsingCalendar();
} else {
mStrToday = getCurrentDateUsingCalendar();
mStrTomorrow = getNextDateUsingCalendar();
}
} else if (mStrCompareStartTime[1].equals("PM") && mStrCompareEndTime[1].equals("AM")) {
mStrToday = getCurrentDateUsingCalendar();
mStrTomorrow = getNextDateUsingCalendar();
} else if (mStrCompareStartTime[1].equals("AM") && mStrCompareEndTime[1].equals("PM")) {
mStrToday = getCurrentDateUsingCalendar();
mStrTomorrow = getCurrentDateUsingCalendar();
}
@SuppressLint("SimpleDateFormat") SimpleDateFormat simpleDateFormat = new SimpleDateFormat("dd-MM-yyyy hh:mm aa");
String mStrDifference = "";
try {
Date date1 = simpleDateFormat.parse(mStrToday + " " + mStrStartTime);
Date date2 = simpleDateFormat.parse(mStrTomorrow + " " + mStrEndTime);
mStrDifference = differenceDatesAndTime(date1, date2);
} catch (ParseException e) {
e.printStackTrace();
}
return mStrDifference;
}
public static String differenceDatesAndTime(Date mDateStart, Date mDateEnd) {
long different = mDateEnd.getTime() - mDateStart.getTime();
long secondsInMilli = 1000;
long minutesInMilli = secondsInMilli * 60;
long hoursInMilli = minutesInMilli * 60;
long daysInMilli = hoursInMilli * 24;
long elapsedDays = different / daysInMilli;
different = different % daysInMilli;
long elapsedHours = different / hoursInMilli;
different = different % hoursInMilli;
long elapsedMinutes = different / minutesInMilli;
long minutes = elapsedHours * 60 + elapsedMinutes;
long result = elapsedDays * 24 * 60 + minutes;
if (0 > result) {
result = result + 720; //result is minus then add 12*60 minutes
}
return result + "";
}
我的输出是E / App ---时间:361分钟