Question

if($_POST['sinitial']=="no")
{
$result = mysqli_query($con,"SELECT * FROM babyname WHERE (iname= '".$_POST['dinitial']."' AND gender= '".$_POST['gender']."' AND ncat= '".$_POST['ncat']."') OR (iname= '".$_POST['dinitial']."' AND gender= '".$_POST['gender']."')");
?>

如果用户输入的是intial＆gt;（dinitial）和性别和名称类别（ncat），我试图从表babynames输出名称。但是，如果用户不想只是名称＆gt;进入特定类别，那么他想查看从＆gt; dinitial开始的所有名称，而不是我的查询应该如何进行？

Answer 1

else
{

$result = mysqli_query($con,"SELECT * FROM babyname WHERE (iname like '".$_POST['dinitial']."%' AND gender= '".$_POST['gender']."' AND ncat= '".$_POST['ncat']."') OR (iname like  '".$_POST['dinitial']."%' AND gender= '".$_POST['gender']."')");

}

Answer 2

让我们试试这种代码..

if($_POST['sinitial']=="no")
{
  $condition = "iname= '".$_POST['dinitial']."' AND gender= '".$_POST['gender']."'";

  if(!empty($_POST['ncat'])) 
     $condition .= "AND ncat= '".$_POST['ncat']."'";

$result = mysqli_query($con,"SELECT * FROM babyname WHERE $condition");

}

Answer 3

if($_POST['sinitial']=="no")
{
 $condition = "iname= '".$_POST['dinitial']."' AND gender= '".$_POST['gender']."'";
if(isset($_POST['ncat']) && !empty($_POST['ncat'])) 
 $condition .= "AND ncat= '".$_POST['ncat']."'";
$result = mysqli_query($con,"SELECT * FROM babyname WHERE $condition");

}

如果用户从表中填写所有3个显示选择值，并且填充2个指定字段显示所有值，则表单中有3个字段

3 个答案: