java中的变形图像与java.awt.Graphics2D

Question

我有这样的形象：

我需要将其变形为这样的图像：

我尝试用很多代码制作它，但我没有解决它。我的最后一次尝试，但最终图像看起来不太好

import java.awt.*;
import java.awt.geom.AffineTransform;
import java.awt.image.AffineTransformOp;
import java.awt.image.BufferedImage;
import java.io.File;
import java.io.IOException;

import javax.imageio.ImageIO;
import javax.swing.JPanel;

class MyPanel2 extends JPanel {

    private final static double DEG_TO_RAD = Math.PI / 360;

    private BufferedImage imageA;
    private BufferedImage imageB;

    static String IMG_URL1 = "img/upg.png";

    public MyPanel2() {

        try {
            imageA = ImageIO.read(new File(IMG_URL1));
        } catch (IOException e) {
            System.err.println("Couldn't find input file. ");
            System.exit(1);
        }

        double rotationRequired = Math.toRadians(90);
        double locationX = imageA.getWidth() / 2;
        double locationY = imageA.getHeight() / 2;
        AffineTransform tx = AffineTransform.getRotateInstance(rotationRequired, locationX, locationY);
        AffineTransformOp op = new AffineTransformOp(tx, AffineTransformOp.TYPE_BILINEAR);

        BufferedImage pom_2 = imageA;
        imageA = new BufferedImage(imageA.getWidth(), imageA.getHeight(), BufferedImage.TYPE_INT_ARGB);

        Graphics2D g2 = imageA.createGraphics();
        g2.setStroke(new BasicStroke(5));
        g2.setColor(Color.BLACK);

        g2.drawImage(op.filter(pom_2, null),10,10, null);

        BufferedImage pom = new BufferedImage(imageA.getWidth()*2, imageA.getHeight(), BufferedImage.TYPE_INT_ARGB);
        Graphics2D g3 = pom.createGraphics();
        g3.setColor(Color.white);
        g3.drawImage(imageA, imageA.getWidth()/5, 0, null);
        imageA = pom;

        imageB = new BufferedImage(imageA.getWidth(), imageA.getWidth(), BufferedImage.TYPE_INT_ARGB);
        // pruchod obrazkem pixel po pixelu
        for (int i = imageB.getWidth(); i > 0; i--) {
            for (int j = imageB.getHeight(); j > 0; j--) {
                int r = (int) (Math.sqrt(i * i + j *j));
                int fi = (int) (Math.atan2(j, i) / DEG_TO_RAD);

                if (r < pom.getWidth() && fi < pom.getHeight()) {
                    imageB.setRGB(i, j, pom.getRGB(r, fi));
                }
            }
        }

        this.setPreferredSize(new Dimension(800, 600));

        imageA = pom_2;
    }

    public void paint(Graphics g) {
        super.paint(g);
        Graphics2D g2 = (Graphics2D)g;

        g2.drawImage(imageA,0,0, null);


        double rotationRequired = Math.toRadians(-135);
        double locationX = imageB.getWidth() / 2;
        double locationY = imageB.getHeight() / 2;
        AffineTransform tx = AffineTransform.getRotateInstance(rotationRequired, locationX, locationY);
        AffineTransformOp op = new AffineTransformOp(tx, AffineTransformOp.TYPE_BILINEAR);

        g2.drawImage(op.filter(imageB, null), 0, -imageB.getHeight()/2, null);
    }
}

使用此代码查看最终图像，如下所示：

Answer 1

我发布了我的解决方案。也许它不优雅，但它有效：

class MyPanel2 extends JPanel {

    private BufferedImage imageA;
    private BufferedImage imageB;
    private double k = 3.0;

    String IMG_URL1 = "img/upg.png";

    public MyPanel2() {

        try {
            imageA = ImageIO.read(new File(IMG_URL1));
        } catch (IOException e) {
            System.err.println("Couldn't find input file. ");
            System.exit(1);
        }

        double radius = k*imageA.getHeight();
        int xC = (int)radius, yC = (int)radius; 
        imageB = new BufferedImage(xC*2,yC, BufferedImage.TYPE_INT_ARGB);

        double r, i, j;
        for(int y = 0; y < imageB.getHeight(); y++) {
            for (int x = 0; x < imageB.getWidth(); x++) {
                r = Math.sqrt((xC-x)*(xC-x)+(yC-y)*(yC-y));
                i = (radius-r);
                j = (-k*imageA.getWidth()/2*(xC-x))/r + imageA.getWidth()/2;
                if (i>=0 && i < imageA.getHeight() && j>=0 && j < imageA.getWidth()) {
                    imageB.setRGB(x, y, imageA.getRGB((int)j, (int)i));
                }
            }
        }
        this.setPreferredSize(new Dimension(800, 600));
    }

    public void paint(Graphics g) {
        super.paint(g);
        Graphics2D g2 = (Graphics2D)g;
        g2.drawImage(imageA, 0, 0, null);
        g2.drawImage(imageB, -imageA.getWidth(), 0, null);
    }
}

Answer 2

你是正确的，因为你得到了极坐标变换。 您只需缩放/翻译源图像和生成的图像（或者等效地，只需转换相对坐标）。

直观地说，在你生成的图像中，fi只是跨越太多，比如PI / 2，而在你想要的图像中，角度跨度非常小（你看到曲率要小得多吗？）

希望这有帮助。