我正在寻找过去的一天而且我没有成功。
我从API获取图像,然后使用以下代码将其下载到位图文件。
private Bitmap DownloadImage(String URL)
{
Bitmap bitmap = null;
InputStream in = null;
try
{
in = OpenHttpConnection(URL);
bitmap = BitmapFactory.decodeStream(in);
in.close();
}
catch (IOException e1)
{
e1.printStackTrace();
}
return bitmap;
}
private InputStream OpenHttpConnection(String urlString) throws IOException
{
InputStream in = null;
int response = -1;
URL url = new URL(urlString);
URLConnection conn = url.openConnection();
if (!(conn instanceof HttpURLConnection))
throw new IOException("Not an HTTP connection");
try
{
HttpURLConnection httpConn = (HttpURLConnection) conn;
httpConn.setAllowUserInteraction(false);
httpConn.setInstanceFollowRedirects(true);
httpConn.setRequestMethod("GET");
httpConn.connect();
response = httpConn.getResponseCode();
if (response == HttpURLConnection.HTTP_OK)
{
in = httpConn.getInputStream();
}
}
catch (Exception ex)
{
throw new IOException("Error connecting");
}
return in;
}
我将图像作为正方形,我想裁剪四个角并使其成为圆形图像。有没有可能实现的方法?
欢迎任何相关的答案。提前谢谢。
答案 0 :(得分:20)
public class MainActivity extends Activity {
@Override
protected void onCreate(Bundle savedInstanceState) {
// TODO Auto-generated method stub
super.onCreate(savedInstanceState);
DrawingView dv = new DrawingView(this);
setContentView(dv);
}
class DrawingView extends View {
Bitmap bitmap;
public DrawingView(Context context) {
super(context);
bitmap = BitmapFactory.decodeResource(context.getResources(),
R.drawable.glossy_overlay);
}
@Override
public void onDraw(Canvas canvas) {
Paint paint = new Paint();
// paint.setColor(Color.CYAN);
canvas.drawBitmap(getclip(), 30, 20, paint);
}
public Bitmap getclip() {
Bitmap output = Bitmap.createBitmap(bitmap.getWidth(),
bitmap.getHeight(), Config.ARGB_8888);
Canvas canvas = new Canvas(output);
final int color = 0xff424242;
final Paint paint = new Paint();
final Rect rect = new Rect(0, 0, bitmap.getWidth(),
bitmap.getHeight());
paint.setAntiAlias(true);
canvas.drawARGB(0, 0, 0, 0);
// paint.setColor(color);
canvas.drawCircle(bitmap.getWidth() / 2,
bitmap.getHeight() / 2, bitmap.getWidth() / 2, paint);
paint.setXfermode(new PorterDuffXfermode(Mode.SRC_IN));
canvas.drawBitmap(bitmap, rect, rect, paint);
return output;
}
}
}
答案 1 :(得分:18)
检索位图后,RoundedBitmapDrawableFactory
可用于从RoundedBitmapDrawable
生成v4 Support Library。然后,Drawable
可以应用于ImageView
或直接提取到Canvas
。
// Create the RoundedBitmapDrawable.
RoundedBitmapDrawable roundDrawable = RoundedBitmapDrawableFactory.create(getResources(), bitmap);
roundDrawable.setCircular(true);
// Apply it to an ImageView.
ImageView imageView = (ImageView)findViewById(R.id.imageView);
imageView.setImageDrawable(roundDrawable);
// Alternatively, draw it to an canvas (e.g. in onDraw where a Canvas is available).
// setBounds since there's no View handling size and positioning.
roundDrawable.setBounds(left, top, right, bottom);
roundDrawable.draw(canvas);
答案 2 :(得分:15)
使用函数blow在位图上绘制圆圈,然后将带圆圈的位图设置为imageview
public static Bitmap getclip(Bitmap bitmap) {
Bitmap output = Bitmap.createBitmap(bitmap.getWidth(),
bitmap.getHeight(), Config.ARGB_8888);
Canvas canvas = new Canvas(output);
final Paint paint = new Paint();
final Rect rect = new Rect(0, 0, bitmap.getWidth(), bitmap.getHeight());
paint.setAntiAlias(true);
canvas.drawARGB(0, 0, 0, 0);
canvas.drawCircle(bitmap.getWidth() / 2, bitmap.getHeight() / 2,
bitmap.getWidth() / 2, paint);
paint.setXfermode(new PorterDuffXfermode(Mode.SRC_IN));
canvas.drawBitmap(bitmap, rect, rect, paint);
return output;
}
答案 3 :(得分:2)
Roman Nurik建议直接使用着色器来做这样的事情,并使用自定义绘图。
我稍微更改了代码以制作椭圆形图像并进行自我测试。效果和表现非常好:
public class StreamDrawable extends Drawable {
private static final boolean USE_VIGNETTE = true;
private final RectF mRect = new RectF();
private final BitmapShader mBitmapShader;
private final Paint mPaint;
private final int mMargin;
public StreamDrawable(Bitmap bitmap, int margin) {
mBitmapShader = new BitmapShader(bitmap,
Shader.TileMode.CLAMP, Shader.TileMode.CLAMP);
mPaint = new Paint();
mPaint.setAntiAlias(true);
mPaint.setShader(mBitmapShader);
mMargin = margin;
}
@Override
protected void onBoundsChange(Rect bounds) {
super.onBoundsChange(bounds);
mRect.set(mMargin, mMargin, bounds.width() - mMargin, bounds.height() - mMargin);
if (USE_VIGNETTE) {
RadialGradient vignette = new RadialGradient(
mRect.centerX(), mRect.centerY() * 1.0f / 0.7f, mRect.centerX() * 1.3f,
new int[] { 0, 0, 0x7f000000 }, new float[] { 0.0f, 0.7f, 1.0f },
Shader.TileMode.CLAMP);
Matrix oval = new Matrix();
oval.setScale(1.0f, 0.7f);
vignette.setLocalMatrix(oval);
mPaint.setShader(
new ComposeShader(mBitmapShader, vignette, PorterDuff.Mode.SRC_OVER));
}
}
@Override
public void draw(Canvas canvas) {
canvas.drawOval(mRect, mPaint);
}
@Override
public int getOpacity() {
return PixelFormat.TRANSLUCENT;
}
@Override
public void setAlpha(int alpha) {
mPaint.setAlpha(alpha);
}
@Override
public void setColorFilter(ColorFilter cf) {
mPaint.setColorFilter(cf);
}
}
答案 4 :(得分:0)
这可以在xml中完成,请在此处查看我的答案: https://stackoverflow.com/a/18287979/665930
<RelativeLayout
android:id="@+id/icon_layout"
android:layout_width="@dimen/icon_mask"
android:layout_height="@dimen/icon_mask"
android:layout_alignParentLeft="true"
android:layout_alignParentTop="true" >
<ImageView
android:id="@+id/icon"
android:layout_width="@dimen/icon"
android:layout_height="@dimen/icon"
android:layout_centerInParent="true"
android:scaleType="fitXY" >
</ImageView>
<ImageView
android:id="@+id/icon_mask"
android:layout_width="@dimen/icon_mask"
android:layout_height="@dimen/icon_mask"
android:layout_centerInParent="true"
android:background="@drawable/circle"
android:scaleType="fitXY" >
</ImageView>
</RelativeLayout>
<?xml version="1.0" encoding="utf-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android" android:shape="oval" >
<gradient android:startColor="#00FFFFFF" android:endColor="#00FFFFFF"
android:angle="270"/>
<stroke android:width="10dp" android:color="#FFAAAAAA"/>
答案 5 :(得分:0)
我尝试了上述解决方案,但对我来说都没有用。这是因为我的手机摄像头不能拍摄正方形图像,而只能拍摄矩形图像。因此,我在@actsai解决方案中进行了一些更改,以始终采用较小的尺寸,然后将图像裁剪成一个圆圈:
func dec<T: Decodable>(from: URL, decodable: T.Type, result: (T) -> Void) {
// your Alamofire logic
let data = try JSONDecoder().decode(popedList, from: result!)
result(data)
}
我使用以下scale属性将新的位图填充到ImageView中:
public static Bitmap getBitmapClip(Bitmap bitmap) {
int maxLenth = bitmap.getWidth() <= bitmap.getHeight() ? bitmap.getWidth() : bitmap.getHeight();
Bitmap output = Bitmap.createBitmap(maxLenth,
maxLenth, Bitmap.Config.ARGB_8888);
Canvas canvas = new Canvas(output);
final Paint paint = new Paint();
final Rect rect = new Rect(0, 0, maxLenth, maxLenth);
paint.setAntiAlias(true);
canvas.drawARGB(0, 0, 0, 0);
canvas.drawCircle(maxLenth / 2, maxLenth / 2,
maxLenth / 2, paint);
paint.setXfermode(new PorterDuffXfermode(PorterDuff.Mode.SRC_IN));
canvas.drawBitmap(bitmap, rect, rect, paint);
return output;
}
答案 6 :(得分:0)
在寻找了很多答案之后,我想到了一个小技巧,该技巧利用了FrameLayout(将子视图叠加成一个堆栈)和椭圆形的stroke属性。这可以用XML轻松完成,而无需太多麻烦和第三方库。
注意:
我们的想法是排除圆周围的区域,并显示圆内部可见的图像内容。
注意:
a。笔划标签中指定的颜色(笔划颜色)是裁剪图像周围的 MaskColor / BackgroundColor 。因为我希望此颜色与我的基本视图(即cardView)的颜色相同。我使用了相同的颜色“白色”。
b。宽度(笔划宽度)设置为很大的值,以至于太厚,无法在中心放置裁剪的图像。
c。还可以通过指定一个比其父级FrameLayout大得多的巨大尺寸来利用在步骤4中创建的ImageView(顶部蒙版层),从而使其在FrameLayout尺寸之外进行扩展。这会用较大的笔触宽度环填充我们感兴趣的遮罩区域。
circle_image.xml
<FrameLayout
xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:app="http://schemas.android.com/apk/res-auto"
android:id="@+id/icon_layout"
android:layout_width="64dp"
android:layout_height="64dp">
<ImageView
android:id="@+id/iv_profile_pic"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:src="@drawable/ic_launcher_background"
android:contentDescription="TODO"/>
<ImageView
android:layout_width="90dp"
android:layout_height="90dp"
android:layout_gravity="center"
android:background="@drawable/circle"
android:scaleType="fitXY" >
</ImageView>
</FrameLayout>
circle_mask.xml
<?xml version="1.0" encoding="utf-8"?>
<shape
xmlns:android="http://schemas.android.com/apk/res/android"
android:shape="oval">
<size android:width="64dp"
android:height="64dp"/>
<solid android:color="@android:color/transparent"/>
<stroke
android:width="18dp"
android:color="@android:color/white" />
</shape>