Question

public String getMessage (int numEggs) {

    int a = numEggs/12;
    int b = numEggs%12;

    if ( numEggs < 0) {
        System.out.println("Invalid number");
    } else {
        System.out.println("Your number of eggs is "+ a +" dozen(s) and "+ b+".");
        return;
    }
}

所以当我尝试在回报中放置一些东西时，我一直得到Type mismatch: cannot convert from int to String;代码有什么问题？我必须使用getMessage (int numEggs)因为它是我给出的问题的一部分。

Answer 1

当我尝试在返回中放入某些内容时，
无法从int转换为String

该方法希望您返回一个String。所以你做不到：

return 1; //ie 1, does not get automatically converted to "1"

但你可以这样做：

return "I'm a String";

Answer 2

我没有Type mismatch: cannot convert from int to String，但错误是：This method must return a result of type String

您的方法中缺少return语句：

public String getMessage(int numEggs) {

    int a = numEggs / 12;
    int b = numEggs % 12;

    if (numEggs < 0) {
        return "Invalid number";
    } else {
        return "Your number of eggs is " + a + " dozen(s) and "
                + b + ".";          
    }
}

即使我将getMessage返回类型更改为void它也不会给我Type mismatch: cannot convert from int to String

public void getMessage(int numEggs) {

    int a = numEggs / 12;
    int b = numEggs % 12;

    if (numEggs < 0) {
        System.out.println("Invalid number");
    } else {
        System.out.println("Your number of eggs is " + a + " dozen(s) and "
                + b + ".");
        return;
    }
}

Answer 3

你需要返回一个字符串吗？如果您只是想打印，只需将返回类型设为无效并删除底部的“返回”。

Answer 4

如果要返回String：

public String getMessage（int numEggs）{

int a = numEggs/12;
int b = numEggs%12;
String strReturn = "";

if ( numEggs < 0) {
    strReturn = "Invalid number";
} else {
    strReturn = "Your number of eggs is "+ a +" dozen(s) and "+ b+".";

}
return strReturn;

}

如果你想在consolse中打印它，那么

public void getMessage（int numEggs）{

int a = numEggs/12;
int b = numEggs%12;

if ( numEggs < 0) {
    System.out.println("Invalid number");
} else {
    System.out.println("Your number of eggs is "+ a +" dozen(s) and "+ b+".");
}

}

类型不匹配：无法从int转换为String

4 个答案: