我的问题与我想的有些不同,我先前问过:Parse JSON to cofigure android application 我有json来自服务器,当我在浏览器源代码中看到它;这就是它的样子
JOSON.config:
<html>
<head></head>
<body>
<pre>
[
{
"sett": " ",
"glHdr": {
"sm": [ ],
"scleHPad": false,
"st": "sbsm"
},
"colrBG": [
23,
105,
184,
100
],
"colrTB": [
0,
0,
0,
0
],
"colrTR": [
255,
255,
255,
100
],
"glFtr": {
"icoSz": "icoSzN",
"sm": [ ],
"scleHPad": false,
"gvNR": 3,
"gvHIT": false,
"gvNC": 3,
"st": "igsm"
},
"statBr": true
},
{
"sm": [
{
"tbico": "b43-jeep.png",
"t": "Welcome!",
"w": "http://google.com/start",
"st": "w",
"wTBL": "wTBLN"
},
{
"t": "Content screen title",
"f": "Eltec%20Spec%20sheet%20Gim%20RD30W.pdf",
"st": "f"
},
{
"tbico": "109-chicken.png",
"t": "Sub menu",
"sm": [
{
"t": "Screen 1",
"st": "f"
},
{
"t": "Screen 2",
"w": "Http://google.com",
"st": "w",
"wTBL": "wTBLT"
}
],
"st": "sm"
},
{
"st": "f"
}
],
"st": "tbm"
}
]
</pre>
</body>
</html>
扫描json的功能:
public void doScanAppConfigJson(){
JSONArray appConfig = null;
// Function for looping json object via ParseJson class.
//Creating JSON Parser instance
JSONParser jParser = new JSONParser();
//Getting json strings from url
JSONObject jsonObject = jParser.getJSONFromUrl(url);
try{
//Getting array of settings
appConfig = jsonObject.getJSONArray(ConfigConstants.TABLE_VIEW_SUB_MENU_CONFIG);
//loop throw all the objects under -sm[]
for (int i = 0; i < appConfig.length(); i++){
JSONObject sm = appConfig.getJSONObject(i);
//Now store each of this json in local constant var.
String tabTitle = sm.getString(TAG_TITLE);
String webAddress = sm.getString(TAG_WEB_ADDRESS);
String screenType = sm.getString(TAG_SCREEN_TYPE);
String fileName = sm.getString(TAG_FILENAME);
}
}catch (JSONException e){
e.printStackTrace();
}
}
getJsonFromUrl方法:
public JSONObject getJSONFromUrl(String url){
//Global authentication for link username and password.
Authenticator.setDefault(new Authenticator() {
protected PasswordAuthentication getPasswordAuthentication(){
return new PasswordAuthentication("username", "password".toCharArray());
}
});
// Making HTTP request
try {
// defaultHttpClient
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(
is, "iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
json = sb.toString();
} catch (Exception e) {
Log.e("Buffer Error", "Error converting result " + e.toString());
}
// try parse the string to a JSON object
try {
jObj = new JSONObject(json);
} catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data " + e.toString());
}
// return JSON String
return jObj;
}
AND ERROR即时获取是:http://cl.ly/image/0z1u2v30341G
现在我猜它是html doctype或其他的bcz,但我找不到什么错误。
问:如何解析此JSON并将其存储在局部变量中? (我没有为json更改服务器端的选项)提前感谢。
答案 0 :(得分:1)
你可以从打开' ['直到关闭'] '开始提取子字符串,然后将其解析为json,在getJSONFromUrl()
中进行更改方法:
public void getJSONFromUrl() {
...
...
json = sb.toString().substring(html.indexOf("["), html.lastIndexOf("]") + 1);
...
}