我正在使用下面提到的json解析数据及其崩溃
JSONObject eachData2 = user6.getJSONObject(n);
我正在尝试从数组中检索lat / lng。请让我知道错误的位置，以及我是否可以使json解析代码比下面的代码更短。我非常感谢任何帮助。谢谢提前。< / p>
String jsonLocation = null;
try {
jsonLocation = converJsonToStringFromAssetFolder("datajson", getBaseContext());
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
JSONObject mainObject = null;
try {
mainObject = new JSONObject(jsonLocation);
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
JSONArray new1 = null;
try {
new1 = mainObject.getJSONArray("data1");
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
for (int i = 0; i < new1.length(); i++) {
JSONObject c = null;
try {
c = (JSONObject) new1.get(i);
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
JSONObject user = null;
try {
user = c.getJSONObject("latlng");
JSONArray user2 = user.getJSONArray("geoset1");
for (int j = 0; j < user2.length(); j++) {
JSONArray user3 = user2.getJSONArray(j);
for (int k = 0; k < user3.length(); k++) {
JSONArray user4 = user3.getJSONArray(k);
for (int l = 0; l < user4.length(); l++) {
JSONArray user5 = user4.getJSONArray(l);
for (int m = 0; m < user5.length(); m++) {
JSONArray user6 = user5.getJSONArray(m);
for (int n = 0; n < user6.length(); n++) {
JSONObject eachData2 = user6.getJSONObject(n);
if (n==0) {
JSONObject eachData = user6.getJSONObject(n);
} else {
JSONObject secondData = user6.getJSONObject(n);
}
}
}
}
}
} }catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
public static String converJsonToStringFromAssetFolder(String fileName,Context context) throws IOException {
AssetManager manager = context.getAssets();
InputStream file = manager.open(fileName);
byte[] data = new byte[file.available()];
file.read(data);
file.close();
return new String(data);
}
}
的Json
{
"dataset": "dataset1",
"data1": [
{
"dataset2": "dataset21",
"dataset3": {
"dataset31": 1,
"LAT": 70.0187,
"LON": "-141.0205"
},
"latlng": {
"latlng1": "latlngset1",
"geoset1": [
[
[
[
70.0187,
-141.0205
],
[
70.1292,
-141.7291
],
[
70.4515,
-144.8163
],
[
70.7471,
-148.4583
],
[
70.7923,
-151.1609
]
]
],
[
[
[
71.147,
-152.6221
],
[
71.4307,
-154.8853
],
[
71.5232,
-156.7529
],
[
71.5232,
-156.7529
],
[
71.5232,
-156.7529
]
]
],
[
[
[
71.1185,
-153.9954
],
[
64.3922,
-167.0142
],
[
64.0554,
-165.7343
],
[
64.0193,
-163.2294
],
[
63.9615,
-162.1143
]
]
]
]
}
}
]
}
答案 0 :(得分：1)
你写了太多for个循环：
user6是int类型：int user6 = user5.getInt(m);
这是一个修复：
JSONObject mainObject = null;
try {
mainObject = new JSONObject(jsonString);
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
JSONArray new1 = null;
try {
new1 = mainObject.getJSONArray("data1");
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
for (int i = 0; i < new1.length(); i++) {
JSONObject c = null;
try {
c = (JSONObject) new1.get(i);
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
JSONObject user = null;
try {
user = c.getJSONObject("latlng");
JSONArray user2 = user.getJSONArray("geoset1");
for (int j = 0; j < user2.length(); j++) {
JSONArray user3 = user2.getJSONArray(j);
for (int k = 0; k < user3.length(); k++) {
JSONArray user4 = user3.getJSONArray(k);
for (int l = 0; l < user4.length(); l++) {
JSONArray user5 = user4.getJSONArray(l);
for (int m = 0; m < user5.length(); m++) {
doubleuser6 = user5.getDouble(m);
System.out.println(user6);
}
}
}
} }catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
输出：
70
-141
70
-141
70
-144
70
-148
70
-151
71
-152
71
-154
71
-156
71
-156
71
-156
71
-153
64
-167
64
-165
64
-163
63
-162
答案 1 :(得分：0)
您好，这看起来很komplex但是如果您愿意使用GSON，可以将其转换为只有几行的JAVA对象。