Question

对于每个期望返回值，如2或4，我想将此值作为单元测试方法的参数传递。但我得到一个例外，即参数不正确。当我删除countExpected参数时，单元测试运行正常，我就无法断言countExpected ...

这种情况在NUnit中是否可行？

[Test, TestCaseSource("VisibleWeekDays")]
public void Test(DayOfWeek[] visibleWeekDaysSetup, int countExpected)
{
    // ARRANGE

    // ACT

    // ASSERT
    Assert.That(periods.Count(),Is.EqualTo(countExpected));
}

private static IEnumerable<TestCaseData> VisibleWeekDays
{
    get
    {
        yield return new TestCaseData(new DayOfWeek[] {DayOfWeek.Sunday}).Returns(2);
        yield return new TestCaseData(new DayOfWeek[] {DayOfWeek.Sunday, DayOfWeek.Monday}).Returns(4);
        // more days...
    }
}

Answer 1

见解释here：

<强> .Returns
从该方法返回的预期结果，该方法必须具有兼容的返回类型。

因此，如果您想使用TestCaseData.Returns()，则需要按以下方式编写测试：

[Test, TestCaseSource("VisibleWeekDays")]
public int Test(DayOfWeek[] visibleWeekDaysSetup)
{
     // ARRANGE

    // ACT

    // ASSERT
    return periods.Count();
}

<强>更新
如果要将期望值作为参数传递，则需要将其作为常规测试用例数据传递。见例：

[Test, TestCaseSource("VisibleWeekDays")]
public void Test(DayOfWeek[] visibleWeekDaysSetup, int countExpected)
{
    ...

    Assert.That(periods.Count(),Is.EqualTo(countExpected));
}

private static IEnumerable<TestCaseData> VisibleWeekDays
{
    get
    {
        yield return new TestCaseData(new DayOfWeek[] {DayOfWeek.Sunday}, 2);
        yield return new TestCaseData(new DayOfWeek[] {DayOfWeek.Sunday, DayOfWeek.Monday}, 4);
        // more days...
    }
}

使用nunit和TestCaseSource以及TestCaseData设置复杂的行测试

1 个答案: