Question

当我在我的数组中插入一个字符串时，我希望发生的是它拒绝字符串并给出一条消息，解释如何只允许在数组中使用整数。而是重复之前插入的整数。

import sys

ArrayWidth = 9

mmWidth = 22

ArrayDivider = '=' * 33
ArrayDivider = ArrayDivider.center(ArrayWidth)

mmDivider = '=' * 28
mmDivider = mmDivider.center(mmWidth)

MaxAndMin = 'Maximum & Minimum'
MaxAndMin = MaxAndMin.center(mmWidth)

Array = 'Array'
Array = Array.center(ArrayWidth)

Numbers = []


while True:
    NumberInput = input('Enter a whole number (Exit the loop by pressing "0"): ')
    try:
        NumberInput2 = int(NumberInput)
        if NumberInput2 == 0:
            break
        if NumberInput2 <= 0:
            print('Please enter a number greater then 0.');
            continue;
    except ValueError:
        print("Error. Non-numeric data was entered.")
    except:
        print("Error with input...")
    Numbers.append(NumberInput2)

print('\n'+ArrayDivider+Array+ArrayDivider)
print(sorted(Numbers, key=int),'\n')
print(mmDivider+MaxAndMin+mmDivider)
print('Maximum Number = {}'.format(max(Numbers)))
print('Minimum Number = {}'.format(min(Numbers)))

Answer 1

无论是否抛出异常，您都会Numbers.append(NumberInput2)。当int提升ValueError时，NumberInput2不会被重新分配并保留旧值。

试试这个：

while True:
    NumberInput = input('Enter a whole number (Exit the loop by pressing "0"): ')
    try:
        NumberInput2 = int(NumberInput)
        if NumberInput2 == 0:
            break
        if NumberInput2 <= 0:
            print('Please enter a number greater then 0.');
            continue
        Numbers.append(NumberInput2)
    except ValueError:
        print("Error. Non-numeric data was entered.")
    except:
        print("Error with input...")

或者，您可以在打印错误消息后continue，就像使用非正输入一样。

当输入字符串时，数组输入第二个整数

1 个答案: