Question

我正在尝试制作一个最好的两个三分之一的摇滚剪刀程序，计算机随机滚动0-2，每个都分配到岩石，纸张或剪刀，然后它比较userInput并为计算机或播放器计算胜利，然后将其加起来。

但是，我无法弄清楚如何使用如果用户输入“剪刀”，程序会知道它也被分配给2（用于比较目的）。

    public static void main(String[] args) {
    Random r = new Random();
    int gameCount = 0;
    int computerWins = 0;
    int playerWins = 0;
    int rock = 0;
    int paper = 1;
    int scissors = 2;
    int playerChoice;
    int computerChoice = r.nextInt(3);

    System.out.println("Welcome to Rock Paper Scissors! Best 2 out of 3!");

    while (gameCount >= 0 && gameCount < 3)
    {
        System.out.println("Enter \"Rock\", \"Paper\", or \"Scissors\"");
        break;
    }
       playerChoice = userInput.nextInt()

        //If player enters anything besides rock, paper, or scissors
        if (playerChoice < 0 || playerChoice >= 3) {
            System.out.println("That wasn't an option");
            computerWins++;
            gameCount++;

          //The game goes on, and the winners are added up!
        } else if (playerChoice == 0 && computerChoice == 1) {
            computerWins++;
            gameCount++;
            System.out.println("Rock v Paper! Computer Wins!\n" +
                    "Player has won " + playerWins + " times and the computer " +
                    "has won " + computerWins + " times");
        } else if (playerChoice == 1 && computerChoice == 0) {
            playerWins++;
            gameCount++;
            System.out.println("Paper v Rock! Player Wins!\n" +
                    "Player has won " + playerWins + " times and the computer " +
                    "has won " + computerWins + " times");
        } else if (playerChoice == 1 && computerChoice == 2) {
            computerWins++;
            gameCount++;
            System.out.println("Paper v Scissors! Computer Wins!\n" +
                    "Player has won " + playerWins + " times and the computer " +
                    "has won " + computerWins + " times");
        } else if (playerChoice == 2 && computerChoice == 1) {
            playerWins++;
            gameCount++;
            System.out.println("Scissors v Paper! Player Wins!\n" +
                    "Player has won " + playerWins + " times and the computer " +
                    "has won " + computerWins + " times");
        } else if (playerChoice == 2 && computerChoice == 0) {
            computerWins++;
            gameCount++;
            System.out.println("Scissors v Rock! Computer Wins!\n" +
                    "Player has won " + playerWins + " times and the computer " +
                    "has won " + computerWins + " times");
        } else if (playerChoice == 0 && computerChoice == 2) {
            playerWins++;
            gameCount++;
            System.out.println("Rock v Scissors! Player Wins!\n" +
                    "Player has won " + playerWins + " times and the computer " +
                    "has won " + computerWins + " times");
        } else if (playerChoice == 0 && computerChoice == 0) {
            gameCount++;
            System.out.println("Rock v Rock! Tie!\n" +
                    "Player has won " + playerWins + " times and the computer " +
                    "has won " + computerWins + " times");
        } else if (playerChoice == 1 && computerChoice == 1) {
            gameCount++;
            System.out.println("Paper v Paper! Tie!\n" +
                    "Player has won " + playerWins + " times and the computer " +
                    "has won " + computerWins + " times");
        } else if (playerChoice == 2 && computerChoice == 2) {
            gameCount++;
            System.out.println("Paper v Paper! Tie!\n" +
                    "Player has won " + playerWins + " times and the computer " +
                    "has won " + computerWins + " times");
        }

        //Check if game count reaches max games then chooses a winner
        if (gameCount == 3 && computerWins > playerWins) {
            System.out.println("The Computer Wins!");
        } else if (gameCount == 3 && computerWins < playerWins) {
            System.out.println("The Player Wins!");
        } else if (gameCount == 3 && computerWins == playerWins) {
            System.out.println("The game is a tie!");
        }
    }
}

Answer 1

所以不要playerChoice = userInput.nextInt();尝试这个：

Scanner sc = new Scanner(System.in);
String input = sc.nextLine();
try {
    playerChoice = Integer.parseInt(input);
} catch (NumberFormatException e) {
    if (input.equalsIgnoreCase("rock")) {
        playerChoice = rock;
    } else if (input.equalsIgnoreCase("paper")) {
        playerChoice = paper;
    } else if (input.equalsIgnoreCase("scissors")) {
        playerChoice = scissors;
    } else {
        // if input is invalid
        playerChoice = -1;
    }
}

由于您使用userInput.nextInt()和playerChoice是一个int并且只能保存整数，因此您需要解析用户的输入。在这种情况下，Integer.parseInt(input)将尝试在用户输入中查找int。如果它不能返回异常;这就是为什么会有一个尝试捕获块的原因。如果它不是int，它将查找每个字符串并将关联的int值分配给playerChoice或-1如果输入无效。然后你的其余代码应该能够在那之后适当地处理playerChoice。

输入的字符串也分配给整数？

1 个答案: