andengine运动事件视图和相机

时间:2013-03-18 13:21:18

标签: android view camera andengine

我使用此代码显示两个视图mRenderSurfaceView和gestureOverlayView:

            relativeLayout = new RelativeLayout(this);
        final FrameLayout.LayoutParams relativeLayoutLayoutParams = new FrameLayout.LayoutParams(RelativeLayout.LayoutParams.FILL_PARENT , RelativeLayout.LayoutParams.FILL_PARENT );

        gestureOverlayView = new GestureOverlayView(this);
        gestureOverlayView.setEnabled(true);

        this.mRenderSurfaceView = new RenderSurfaceView(this);
        this.mRenderSurfaceView.setRenderer(mEngine);
        surfaceViewLayoutParams = new RelativeLayout.LayoutParams(super.createSurfaceViewLayoutParams());          

        gestureOverlayView.addOnGesturePerformedListener(this);

        relativeLayout.addView(this.mRenderSurfaceView, surfaceViewLayoutParams);
        relativeLayout.addView(gestureOverlayView, 1248,1152);
        gestureOverlayView.setVisibility(View.GONE);
        this.setContentView(relativeLayout, relativeLayoutLayoutParams);

我画了这个:

@Override
    public boolean onTouch(View v, MotionEvent paramMotionEvent) {
    //TODO Auto-generated method stub   

if(paramMotionEvent.getAction() == MotionEvent.ACTION_DOWN) {
     isDrawing = true;

 }
//TouchEvent
 if(paramMotionEvent.getAction() == MotionEvent.ACTION_UP) {
    isDrawing = false;
    rec = new Rectangle[250];
    Arrays.fill( rec, null );
    irec=0; 
 }
 if (isDrawing = true) {

    if (rec[249]!=null){
     return false;
 }


    rec[irec] = new Rectangle(paramMotionEvent.getX(), paramMotionEvent.getY(), 1, 1);
    if (irec != 0) {
       Line l = new Line(rec[irec-1].getX(), rec[irec-1].getY(), rec[irec].getX(), rec[irec].getY());
       l.setColor(0.5f, 1f, 0.3f);
       mScene.attachChild(l);
    }
    irec++;
 }
 return true;
 }

并在OnloadScene中我gestureOverlayView.setOnTouchListener(this);

我的场景做1248 * 1152,问题是公共布尔onTouch工作正常,如果我在向左,但如果在场景中向下移动或向右移动绘制。如何制作具有良好宽度和高度的视图(我猜这是问题,这保持相机比例)?

如果我使用mScene.setOnSceneTouchListener,绘制就可以,但手势不起作用......

1 个答案:

答案 0 :(得分:0)

由velocityOnScreenControl.attachChild(l)解决; (private AnalogOnScreenControl velocityOnScreenControl;)使用AnalogOnScreenControl示例。