解码DNS标头

时间:2013-03-16 23:32:02

标签: c# dns header sharppcap

我正在尝试在c#中解码DNS数据包,虽然这并不重要,但我正在使用 SharpPcap

一切运作良好,但似乎 QR RCODE 字段返回错误的值。我将我的结果与Wireshark的结果进行比较。

即使消息是请求,QR始终为1(响应)。另一个奇怪的事情是,当消息是查询时返回码为0,当消息是响应时返回码为1。

我用来查找DNS标头的其中一个网站是this一个。这里有什么我想念的吗?我用来解码数据包的代码是:(数据是一个包含有效载荷数据的字节数组)

//TransactionID 16 bits (This is correct)
//Not sure why second byte has to be first but that's how wireshark displays it
transactionID = new byte[] { data[1], data[0] }; 

//Flags 16 bits
isResponse = Utilities.getBit(data[2], 0); //always returns 1

//What I'm doing here is converting the boolean returned by getBit into a
//1 or 0 which is used to create a string which will then be converted
//into a UInt16 (If there's an easier way to do this please let me know)
OpCode = Convert.ToUInt16(Convert.ToUInt16(Utilities.getBit(data[2], 1)).ToString() +
         Convert.ToUInt16(Utilities.getBit(data[2], 2)).ToString() +
         Convert.ToUInt16(Utilities.getBit(data[2], 3)).ToString() +
         Convert.ToUInt16(Utilities.getBit(data[2], 4)).ToString(), 2);

//These seem correct (Untested though since wireshark doesn't display them)
authAnswer = Utilities.getBit(data[2], 5);
truncation = Utilities.getBit(data[2], 6);
recursionDesired = Utilities.getBit(data[2], 7);

recursionAvail = Utilities.getBit(data[3], 0);
//skip 3 bits here (reserved and set to 0)...

//ReturnCode returns 0 for queries and 1 for responses, this is pretty weird
returnCode = Convert.ToUInt16(Convert.ToUInt16(Utilities.getBit(data[3], 4)).ToString() +
             Convert.ToUInt16(Utilities.getBit(data[3], 5)).ToString() +
             Convert.ToUInt16(Utilities.getBit(data[3], 6)).ToString() +
             Convert.ToUInt16(Utilities.getBit(data[3], 7)).ToString(), 2);

//Questions count, Answers count, ARR count, Additional ARR: 1 byte each
//These are correct
questionsCount = Convert.ToUInt16(data[4] * 256 + data[5]);
answersCount = Convert.ToUInt16(data[6] * 256 + data[7]);
authorityRRs = Convert.ToUInt16(data[8] * 256 + data[9]);
additionalRRs = Convert.ToUInt16(data[10] * 256 + data[11]);

getBit方法在这里:

public static bool getBit(byte b, int index) {
    //Logical AND with number to find if bit is 0 or 1
    //Shift by index to represent value in binary (2^index)
    bool bit = (b & (1 << index)) != 0;

    return (bit);
}

1 个答案:

答案 0 :(得分:2)

您是否尝试过使用Pcap.Net?它完全支持DNS,因此您无需手动解码任何内容。