我正在尝试使用google maps v3 api创建地图。我在互联网上找到了以下代码,我想在地图窗口中显示纬度和逻辑而不是地址。
<script>
function initialize() {
var mapOptions = {
center: new google.maps.LatLng(-33.8688, 151.2195),
zoom: 13,
mapTypeId: google.maps.MapTypeId.ROADMAP
};
var map = new google.maps.Map(document.getElementById('map_canvas'),
mapOptions);
var input = document.getElementById('searchTextField');
var autocomplete = new google.maps.places.Autocomplete(input);
autocomplete.bindTo('bounds', map);
var infowindow = new google.maps.InfoWindow();
var marker = new google.maps.Marker({
map: map
});
google.maps.event.addListener(autocomplete, 'place_changed', function() {
infowindow.close();
marker.setVisible(false);
input.className = '';
var place = autocomplete.getPlace();
if (!place.geometry) {
// Inform the user that the place was not found and return.
input.className = 'notfound';
return;
}
// If the place has a geometry, then present it on a map.
if (place.geometry.viewport) {
map.fitBounds(place.geometry.viewport);
} else {
map.setCenter(place.geometry.location);
map.setZoom(17); // Why 17? Because it looks good.
}
var image = {
url: place.icon,
size: new google.maps.Size(71, 71),
origin: new google.maps.Point(0, 0),
anchor: new google.maps.Point(17, 34),
scaledSize: new google.maps.Size(35, 35)
};
marker.setIcon(image);
marker.setPosition(place.geometry.location);
marker.setVisible(true);
var address = '';
if (place.address_components) {
address = [
(place.address_components[0] && place.address_components[0].short_name || ''),
(place.address_components[1] && place.address_components[1].short_name || ''),
(place.address_components[2] && place.address_components[2].short_name || '')
].join(' ');
}
infowindow.setContent('<div><strong>' + place.name + '</strong><br>' + address);
infowindow.open(map, marker);
});
请有人帮助我获取并显示纬度和经度。非常感谢你。
答案 0 :(得分:11)
你在哪里
var address = '';
if (place.address_components) {
address = [
(place.address_components[0] && place.address_components[0].short_name || ''),
(place.address_components[1] && place.address_components[1].short_name || ''),
(place.address_components[2] && place.address_components[2].short_name || '')
].join(' ');
}
infowindow.setContent('<div><strong>' + place.name + '</strong><br>' + address);
infowindow.open(map, marker);
将infowindow行更改为
infowindow.setContent('<div><strong>' + place.name + '</strong><br>' + place.geometry.location.lat() + ',' + place.geometry.location.lng());
答案 1 :(得分:9)
更简单的解决方案将是:
var address = "New Delhi"
$.ajax({
url:"http://maps.googleapis.com/maps/api/geocode/json?address="+address+"&sensor=false",
type: "POST",
success:function(res){
console.log(res.results[0].geometry.location.lat);
console.log(res.results[0].geometry.location.lng);
}
});
干杯
答案 2 :(得分:7)
看一下这段代码..
<!DOCTYPE html>
<html>
<head>
<script src="https://maps.googleapis.com/maps/api/js?v=3.exp&sensor=false&libraries=places"></script>
<script>
function initialize() {
var address = 'Kolkata';
geocoder = new google.maps.Geocoder();
geocoder.geocode({
'address': address
}, function(results, status) {
var lat=document.getElementById("lat").innerHTML=results[0].geometry.location.lat();
var lng=document.getElementById("lng").innerHTML=results[0].geometry.location.lng();
});
}
google.maps.event.addDomListener(window, 'load', initialize);
</script>
</head>
<body>
<p id="lat"></p>
<p id="lng"></p>
</body>
</html>
答案 3 :(得分:2)
看起来您可能正在寻找常规地理位置的东西?这是我从一个项目获取用户的lat / long
的片段触发show_user_location();开始地理位置API。
function show_user_location(){
navigator.geolocation.getCurrentPosition(display_user_location, error_response);
}
function display_user_location(user_position){
var lat = user_position.coords.latitude;
var lon = user_position.coords.longitude;
// once we get here make that AJAX query
// #loc.value="<p>Your latitude is: "+lat+", your longitude is: "+lon+"</p>"+ "<p><a href='http://maps.google.com/?q="+lat+","+lon+"'>View your location on Google Maps</a></p>";
// I often put the lat/lon in a hidden form for later retrieval here.
// value = document.getElementById('lat').value;
// value = document.getElementById('lat').value;
document.getElementById("lat").value = lat;
document.getElementById("long").value = lon;
}
答案 4 :(得分:1)
如果您想要地图任何部分的纬度和长度,请尝试添加地图的点击侦听器而不是标记。代码应如下所示:
var infowindow = new google.maps.InfoWindow();
var service = new google.maps.places.PlacesService(map);
service.getDetails({
placeId: 'ChIJN1t_tDeuEmsRUsoyG83frY4'
},function(place,status){
if(status === google.maps.places.PlacesServiceStatus.OK)
{
var marker = new google.maps.Marker({
map:map,
position: place.geometry.location
});
google.maps.event.addListener(map, 'click', function(e) {
infowindow.setContent('<div>'+'Longitute'+'<strong>' + e.latLng.lng() + '</strong><br>' +
'Latitude:'+'<strong>' + e.latLng.lat()+'</strong>' + '</div>');
infowindow.open(map, this);
});
}
});
这将使用信息窗口显示地图上任何位置的纬度和长度。
答案 5 :(得分:0)
我创建了一个小组件来用React
进行说明。不过,它是相同的API
。我认为这可能会有所帮助。
import React, { useState } from 'react';
import PropTypes from 'prop-types';
import { GoogleApiWrapper } from 'google-maps-react';
const SearchLocation = ({ google }) => {
const [inputData, setInputData] = useState('');
const handleChange = ({ target: { value } }) => {
if (value) {
setInputData(value);
const autoCompleteService = new google.maps.places.AutocompleteService();
autoCompleteService.getPlacePredictions(
{ input: value },
(predictions, status) => {
if (status === google.maps.places.PlacesServiceStatus.OK) {
// update prediction, so that user can click on the predicted address
const updatePredictions = (predictions) => {};
// or get the coordinate of one prediction
if (predictions.length > 0) {
geoCodeLocation(predictions[0]);
}
}
}
);
}
};
const geoCodeLocation = (suggestion) => {
const placeId = suggestion.place_id;
const GeoCoder = new google.maps.Geocoder();
GeoCoder.geocode({ placeId }, (response) => {
const lattitude = response[0].geometry.location.lat();
const longitude = response[0].geometry.location.lng();
const coordinates = [longitude, lattitude];
// save coordinate and suggestion
const selectLocation = ({ coordinates, suggestion }) => {};
});
};
return (
<div>
<input
type="text"
name="searchLocation"
placeholder="Enter your address..."
className="text-field"
onChange={handleChange}
/>
{/* handle suggestion */}
</div>
);
};
export default GoogleApiWrapper({
apiKey: process.env.GOOGLE_API_KEY,
v: '3'
})(SearchLocation);
SearchLocation.defaultProps = {};
SearchLocation.propTypes = {
google: PropTypes.shape({}).isRequired,
};