Question

在常规SQL中，每次调用.NEXTVAL时，我的序列都会递增：

SELECT PDF_DATOS_TITULO_ID_SEQ.CURRVAL FROM DUAL; -- 54
SELECT PDF_DATOS_TITULO_ID_SEQ.NEXTVAL FROM DUAL; -- 55
SELECT PDF_DATOS_TITULO_ID_SEQ.NEXTVAL FROM DUAL; -- 56
SELECT PDF_DATOS_TITULO_ID_SEQ.NEXTVAL FROM DUAL; -- 57
SELECT PDF_DATOS_TITULO_ID_SEQ.CURRVAL FROM DUAL; -- 57 (54+3, correct)

但是，在PL / SQL块内的动态SQL中，它不会递增：

SELECT PDF_DATOS_TITULO_ID_SEQ.CURRVAL FROM DUAL; -- 57
BEGIN
    EXECUTE IMMEDIATE 'SELECT PDF_DATOS_TITULO_ID_SEQ.NEXTVAL FROM DUAL';
    EXECUTE IMMEDIATE 'SELECT PDF_DATOS_TITULO_ID_SEQ.NEXTVAL FROM DUAL';
    EXECUTE IMMEDIATE 'SELECT PDF_DATOS_TITULO_ID_SEQ.NEXTVAL FROM DUAL';
END;
/
SELECT PDF_DATOS_TITULO_ID_SEQ.CURRVAL FROM DUAL; -- 57

...除非我将值存储到变量中：

SELECT PDF_DATOS_TITULO_ID_SEQ.CURRVAL FROM DUAL; -- 57 (!)
DECLARE
    FOO INTEGER;
BEGIN
    EXECUTE IMMEDIATE 'SELECT PDF_DATOS_TITULO_ID_SEQ.NEXTVAL FROM DUAL' INTO FOO;
    EXECUTE IMMEDIATE 'SELECT PDF_DATOS_TITULO_ID_SEQ.NEXTVAL FROM DUAL' INTO FOO;
    EXECUTE IMMEDIATE 'SELECT PDF_DATOS_TITULO_ID_SEQ.NEXTVAL FROM DUAL' INTO FOO;
END;
/
SELECT PDF_DATOS_TITULO_ID_SEQ.CURRVAL FROM DUAL; -- 60 (57+3, correct)

解释是什么？它是EXECUTE IMMEDIATE的记录行为吗？

_{在你提出要求之前，SQL需要是动态的，因为序列名是可变的。}

Answer 1

当您省略或批量返回子句时，Oracle将仅解析sql但不会从中发出任何提取。在文档中没有明确说明会发生这种情况，但是文档确实指定当你有1行返回时你应该使用INTO，如果你有可能有多行返回，那么你应该使用INTO。

e.g：

SQL> create sequence testseq;

Sequence created.

SQL> alter session set events '10046 trace name context forever';

Session altered.

SQL> exec execute immediate 'select testseq.nextval from dual';

PL/SQL procedure successfully completed.

SQL> alter session set events '10046 trace name context off';

Session altered.

SQL> exit

我们在跟踪中看到Oracle没有对FETCH阶段感到烦恼：

=====================
PARSING IN CURSOR #140341213531640 len=32 dep=1 uid=83 oct=3 lid=83 tim=1363260261727946 hv=956010684 ad='7ac66b58' sqlid='56jwk2hwgr45w'
select testseq.nextval from dual
END OF STMT
PARSE #140341213531640:c=4001,e=50473,p=0,cr=2,cu=0,mis=1,r=0,dep=1,og=1,plh=112670795,tim=1363260261727944
EXEC #140341213531640:c=0,e=219,p=0,cr=0,cu=0,mis=0,r=0,dep=1,og=1,plh=112670795,tim=1363260261728249
STAT #140341213531640 id=1 cnt=0 pid=0 pos=1 obj=79530 op='SEQUENCE  TESTSEQ (cr=0 pr=0 pw=0 time=181 us)'
STAT #140341213531640 id=2 cnt=0 pid=1 pos=1 obj=0 op='FAST DUAL  (cr=0 pr=0 pw=0 time=1 us cost=2 size=0 card=1)'
CLOSE #140341213531640:c=4001,e=24391,dep=1,type=3,tim=1363260261752736
EXEC #140341212444728:c=8002,e=75407,p=0,cr=2,cu=0,mis=0,r=1,dep=0,og=1,plh=0,tim=1363260261752783

*** 2013-03-14 11:24:29.866
CLOSE #140341212444728:c=0,e=37,dep=0,type=0,tim=1363260269866098
=====================

VS

SQL> alter session set events '10046 trace name context forever';

Session altered.

SQL> var a number
SQL> exec execute immediate 'select testseq.nextval from dual' into :a;

PL/SQL procedure successfully completed.

SQL> alter session set events '10046 trace name context off';

Session altered.

现在：

PARSING IN CURSOR #139830768042232 len=32 dep=1 uid=83 oct=3 lid=83 tim=1363260428931803 hv=956010684 ad='7ac66b58' sqlid='56jwk2hwgr45w'
select testseq.nextval from dual
END OF STMT
PARSE #139830768042232:c=0,e=38,p=0,cr=0,cu=0,mis=0,r=0,dep=1,og=1,plh=112670795,tim=1363260428931802
EXEC #139830768042232:c=0,e=86,p=0,cr=0,cu=0,mis=0,r=0,dep=1,og=1,plh=112670795,tim=1363260428931917
FETCH #139830768042232:c=0,e=22,p=0,cr=0,cu=0,mis=0,r=1,dep=1,og=1,plh=112670795,tim=1363260428931980
STAT #139830768042232 id=1 cnt=1 pid=0 pos=1 obj=79530 op='SEQUENCE  TESTSEQ (cr=0 pr=0 pw=0 time=39 us)'
STAT #139830768042232 id=2 cnt=1 pid=1 pos=1 obj=0 op='FAST DUAL  (cr=0 pr=0 pw=0 time=2 us cost=2 size=0 card=1)'
CLOSE #139830768042232:c=0,e=0,dep=1,type=3,tim=1363260428931980
EXEC #139830768045912:c=0,e=294,p=0,cr=0,cu=0,mis=0,r=1,dep=0,og=1,plh=0,tim=1363260428931980

*** 2013-03-14 11:27:13.138
CLOSE #139830768045912:c=0,e=45,dep=0,type=0,tim=1363260433138490
=====================

可以看到FETCH。我认为理想情况下，Oracle应该在用户发出没有定义INTO / BULK INTO的选择的情况下抛出错误。

除非我存储值，否则序列不会递增

1 个答案: