关于id问题的PHP内连接

Question

我这里有这个脚本

select distinct 
FirstName, 
LastName, 
table_2.status, 
'Shop' as receiver
from table_1
inner join table_2 on table_1.key_2 = table_2.'SHOP-'id
order by FirstName, LastName

key_2字段有像SHOP-121这样的ID，而表2中的id就是数字121.

如何从key_2中删除SHOP-或将SHOP-添加到id？

Answer 1

使用CONCAT

table_1.key_2 = CONCAT('SHOP-', table_2.id)

请记住，这将执行全表扫描，导致它在大型数据库上变慢。