Question

我创建了一个INNER JOIN查询，如下所示，并想知道如何让它工作？我需要HomeTeam和AwayTeam在查询中等于TeamID。任何帮助将非常感激。感谢

$result = mysqli_query($con,"SELECT results.*,team.TeamName 
                             FROM results 
                                INNER JOIN team ON team.TeamID = results.HomeTeam 
                                INNER JOIN team on team.TeamID = results.AwayTeam");

Answer 1

您需要为包含两次的表使用别名。否则mysql无法区分这两者。

为了能够轻松处理结果，您可以对选择的名称执行相同的操作。

类似的东西：

SELECT 
    results.*, 
    t1.TeamName AS TeamNameHome,
    t2.TeamName AS TeamNameAway
FROM results 
INNER JOIN team t1
    ON t1.TeamID = results.HomeTeam 
INNER JOIN team t2
    ON t2.TeamID = results.AwayTeam

MySQL INNER JOIN查询问题

1 个答案: