Question

    var JSONObj='[{"rmaNumber":null,"orderReferenceNumber":"referene45","orderStatus":"Pending","dateRequested":null,"dateApproved":null,"segateAddress":null,"billingAddress":null,"shippingAddress":null,"returnForCredit":{"requested":null,"received":null,"shipped":35,"credited":45,"invoiceAmount":null},"returnForExchange":{"requested":null,"received":null,"shipped":35,"credited":45,"invoiceAmount":null},"totals":null}]'
    var parsedJSON = eval('(\'+JSONObj+\')');    
    var result=parsedJSON.result;
    var count=parsedJSON.count;
    alert('result:'+result+' count:'+count);

在警告中给出undefined：undefined

Answer 1

您应该使用JSON.parse()：

var parsedJSON = JSON.parse(JSONObj);
console.log(parsedJSON[0].orderStatus);  // "Pending"

注意：此方法仅受现代浏览器支持。了解浏览器兼容性here。

Answer 2

var JSONObj='[{"rmaNumber":null,"orderReferenceNumber":"referene45","orderStatus":"Pending","dateRequested":null,"dateApproved":null,"segateAddress":null,"billingAddress":null,"shippingAddress":null,"returnForCredit":{"requested":null,"received":null,"shipped":35,"credited":45,"invoiceAmount":null},"returnForExchange":{"requested":null,"received":null,"shipped":35,"credited":45,"invoiceAmount":null},"totals":null}]';

var parsedJSON = JSON.parse(JSONObj);    
var result=parsedJSON.result;
var count=parsedJSON.count;
alert('result:'+result+' count:'+count);

但是，您没有任何名为“result”或“count”的JSON字段，因此这些字段将是未定义的。

Answer 3

您可以改为使用JSON.parse。

对于不支持JSON.parse nativly（MSIE）的浏览器，您可以使用第三方库，例如json2或json3。

var parsedJSON = JSON.parse(JSONObj);

Answer 4

你有引用问题。

您可以通过替换

来解决此问题

var parsedJSON = eval('(\'+JSONObj+\')');

与

var parsedJSON = eval('('+JSONObj+')');

但这里没有理由不使用JSON.parse。

Answer 5

var parsedJSON = eval(JSONObj);

这将为您提供已解析的JSON对象。但是在Json对象中没有属性名result，count也是如此。如果您想计算数组，那么您只需使用length来代替parsedJSON.length

Answer 6

试

var JSONObj='[{"rmaNumber":null,"orderReferenceNumber":"referene45","orderStatus":"Pending","dateRequested":null,"dateApproved":null,"segateAddress":null,"billingAddress":null,"shippingAddress":null,"returnForCredit":{"requested":null,"received":null,"shipped":35,"credited":45,"invoiceAmount":null},"returnForExchange":{"requested":null,"received":null,"shipped":35,"credited":45,"invoiceAmount":null},"totals":null}]';

 eval("var  parsedJSON =" + JSONObj);

Answer 7

第一件事：

var parsedJSON = eval('(\'+JSONObj+\')');

应该是

var parsedJSON = eval('('+JSONObj+')');

第二件事：
我没有看到任何result或count对象是json字符串

第三件事：
json中的数据在数组中，所以如果对象中存在任何对象result，则在数组中，应该使用{{1}访问它}

无法将JSON字符串转换为javascript对象

7 个答案: