Question

我需要一些帮助将JSON字符串转换为JSON对象。这是我的变量：

var myString= "{ title: 'mySchema'," + "root: {id:'"  + var1 + "'," + "title:'" + var2  + "'," + "subtitle:'" + var3 + "',";
childrenVar = myString + "{ id: '" + var1 + "'," + "title: '" + var2 + "'," + "subtitle: '" + var3 + "'," + "type: '" +  var4 + "'";

myString= getChildNodes(tasksEntries, head, liststring);
myString= myString + "},";}
myString= myString+ "]}}"; }
myString= childrenVar;
myString= childrenVar;
JSON.stringify(myString);
$.parseJSON(myString);

我在调试时输出myString：

{title: 'mySchema',
 root: { 
     id:'1',
     title:'oOB', 
     subtitle:'Hang Chaw', 
     children: [
       { 
         id: '2',
         title: 'OaK',
         subtitle: 'Ke Man',
         type: 'VA'
       },
       { 
         id: '3',
         title: 'OOB', 
         subtitle: 'Hung Aslew',
         type: 'VA'
       },
     ]
   }
};

Answer 1

删除close array（]之前的最后一个逗号。

Answer 2

您还需要围绕对象键引用。一个合适的JSON字符串看起来像下面的字符串。 jQuery.parseJSON

这是一个示例Fiddle，其中字符串转换为对象，然后记录到控制台。

var myString = '{"title": "mySchema","root": {"id":"1","title":"oOB","subtitle":"Hang Chaw","children": [{ "id": "2","title": "OaK","subtitle": "Ke Man","type": "VA"},{ "id": "3","title": "OOB","subtitle": "Hung Aslew","type": "VA"}]}}';

使用JSON.parse，这是相同的Fiddle。最新版本的JavaScript本身支持JSON。如果您只使用jQuery来解析JSON字符串，那么您应该使用JSON.parse，而不是包含jQuery库。

将动态字符串转换为JSON对象

2 个答案: