Question

我正在使用jQuery作为标准库。但是，我不得不使用Prototype来执行一个简单的功能。但这引起了冲突！

如何使下面的代码与jQuery一起使用并分配Prototype？

<script type="text/javascript" language="javascript">
function trim(str){str = str.replace(/^\s*$/, '');return str;}
function signup() { 
    var email   = trim($F("email"));
    var name    = trim($F("name"));
    //EMAIL VALIDATION
    var goodEmail = email.match(/\b(^(\S+@).+((\.com)|(\.net)|(\.edu)|(\.mil)|(\.gov)|(\.org)|(\.info)|(\.sex)|(\.biz)|(\.aero)|(\.coop)|(\.museum)|(\.name)|(\.pro)|(\.arpa)|(\.asia)|(\.cat)|(\.int)|(\.jobs)|(\.tel)|(\.travel)|(\.xxx)|(\..{2,2}))$)\b/gi);
    apos=email.indexOf("@");dotpos = email.lastIndexOf(".");lastpos=email.length-1;
    var badEmail    = (apos<1 || dotpos-apos<2 || lastpos-dotpos<2);
    if (name=="") {
        $("myResponse").style.display="inline";                 //3 lines to show and style the error message
        $("myResponse").style.color="white";                        // there are more ways to do it using css classes for example.
        $("myResponse").innerHTML="Por favor, digite seu nome";     // you could also make an error function.
        $("name").clear(); $("name").focus();                                       // clear the field and put cursor inside
        return false;
        /*  YOU CAN REPEAT THE ABOVE ELSE IF BLOCK IF YOU HAD OTHER FIELDS IN YOUR FORM, 
            LIKE LAST NAME, ADDRESS ETC. AS AN EXAMPLE SEE HOW THE NAME IS HANDLED AND REPEAT
        */
    }
    else if (email=="" || !goodEmail || badEmail) {
        $("myResponse").style.display="inline";             //3 lines to show and style the error message
        $("myResponse").style.color="white";
        $("myResponse").innerHTML="Por favor, insira um email válido";
        $("email").focus();
        return false;
    }
    else {
        //YOU MAY WANT TO CHANGE THE URL IN THE LINE BELOW
        var url = "includes/optIn.php";
        var params =  $("subform").serialize();
        new Ajax.Request(url, {onComplete:showResponse, onException:showException, onFailure:showException, asynchronous:true, method:'post', evalScripts:false, postBody:params});
        $("submit", "myResponse").invoke('hide');   // Hide the buttom and the message
        $("loading").show();                        // show the loading image.
        return false;
    }
}
function showResponse(req)  {
        $("loading").hide();
        $("myResponse").innerHTML=req.responseText; //Writes the "Thank you" message that comes from optIn.php and styles it.
        $("myResponse").style.display="inline";
        $("myResponse").style.color="white";
        $("submit").show();
        $("name", "email").invoke('clear'); 
}
function showException(req) {
    $("myResponse").innerHTML=req.responseText;
    alert("A comunicação com o servidor falhou. Tente novamente!");
    $("loading", "myResponse").invoke('hide');
    $("submit").show();
    $("name", "email").invoke('clear');    
}
</script>

Answer 1

你试试jQuery.noConflict（）吗？

http://api.jquery.com/jQuery.noConflict/

Answer 2

对于jQuery，您需要更改选择器以使用# id selector。此外，jQuery不区分集合和单个元素，它总是调用集合中每个元素的方法。

特别是，您将使用.val()，.css()，.show()，.hide()和.focus()方法来替换Prototype和本机DOM方法。此外，您将切换到jQuery.ajax功能 - 在API docs中查找。

Answer 3

以下是您需要完成的一些替换

$F('id') => $('#id').val();

//directly
$("id").style.display='inline' => $('#id')[0].style.display='inline';

//the "jQuery" way
$("id").style.display='inline' => $('#id').css('display','inline')

$("id").style.color="white" => $("#myResponse").css('color',"white")

$("id").innerHTML="Por favor, digite seu nome" => $('#id').html("Por favor, digite seu nome")

//.clear() has no direct equivalent method but this is close
$("id").clear() => $('#id').val(null)

$("subform").serialize() => $("#subform").serialize()

$("submit", "myResponse").invoke('hide') => $("#submit, #myResponse").hide()

这些都是简单的替换，我会留给你做Ajax.Request()转换为$.ajax()

如何使这个代码与jQuery一起使用？

3 个答案: