Question

尝试从csv文件中获取数据这就是我的csv文件的外观：

a,0,b,2,c,6,G,4,l,6,mi,2,m,0,s,4
a,2,b,2,c,0,G,4,l,6,mi,4,m,0,s,6
a,4,b,2,c,6,G,6,l,2,mi,4,m,0,s,0
a,2,b,0,c,2,G,6,l,4,mi,4,m,0,s,6
a,2,b,2,c,6,G,4,l,0,mi,6,m,0,s,4
a,2,b,6,c,0,G,6,l,0,mi,4,m,2,s,4
a,0,b,6,c,4,G,2,l,0,mi,6,m,4,s,2
a,6,b,6,c,4,G,0,l,0,mi,2,m,4,s,2

所以，例如在行[0]中，取决于line 1,3,5,7,9,11,13,15中的数值我需要在0,2,4,6,10,12,14

中获取值

更深层的例子：从第1行：我需要得到

 a,m = 0
b,mi = 2
c,l = 6
G,s =4

最后，我要补充一下，哪两个组合最高。所以基本上是每个人的总和。

为了做到这一点：

# Sanitize filelist to keep only *.csv files    
def sanitize_filelist(filelist):

    sanitized_filelist = []

    # Keep only the log file
    for file in range(len(filelist)):
        if string.lower(filelist[file][-4:]) == '.csv':
            sanitized_filelist += [filelist[file]]
#    print sanitized_filelist
    return sanitized_filelist


def parse_files(dataset_path,file):
    threads = [0,2,4,6,10,12,14]
    coreid  = [1,3,5,7,9,11,13,15]
    cores = [0,2,4,6]
    thread_data = [[],[],[],[],[],[],[]]
    #core = [[],[],[],[],[],[],[]]
        threadcorecount = [[0 for a in range(0,4)] for b in range(0,8)]
    dataset = csv.reader(open(dataset_path, 'rb'), delimiter=',')
    for line in dataset:
        #print line
        for thread in range(len(threads)):
            thread_data[thread] = line[threads[thread]]
        for core in range(len(threads)):
            if line[coreid[core]] == cores[0]:
                sub = core - 1
                print thread_data[sub],cores[0]

我写了这个片段 - 仍然是一个测试版本。我无法获得价值和打印。没有错误..我不明白错误是什么。

Answer 1

如果我已理解您的所有请求，则以下代码应该可以解决问题：如果您想访问每行中的值，可以使用results变量（或保存counter变量某处），以及sorted_results来计算可能的排列。

一些参考文献：

lambda functions（现在由更长的代码替换）
Counter class
sort dictionary by value（用于sorted_results）
operator module（用于sorted_results）

这是代码：

import csv
from collections import Counter
import operator

def parse_files(dataset_path,f):  # please avoid using reserved words like file
    threads = range(0,16,2)
    dataset = csv.reader(open(dataset_path,'rb'), delimiter=',')
    results = []
    for line in dataset:
        counter = {str(x):[] for x in range(0,8,2)}
        # map(lambda x:counter[line[x+1]].append(line[x]), threads)
        # map(lambda ...) is just a more pythonic way to write the following two lines
        for index in threads:
            counter[line[index+1]].append(line[index])
        # now counter is something like 
        #{'0': ['c', 'l'], '2': ['a', 'm'], '4': ['mi', 's'], '6': ['b', 'G']}

        results.extend([','.join(v)+'='+k for k,v in counter.items()])
        # in results, I'm appending something like this:
        # {'c,l=6', 'a,m=0', 'b,mi=2', 'G,s=4'}

    sorted_results = sorted(dict(Counter(results)).iteritems(), key=operator.itemgetter(1), reverse=True)
    print '\n'.join(['The couple %s appears %d times'%el for el in sorted_results])

    # >>> The couple a,b=2 appears 2 times
    # >>> The couple c,m=4 appears 2 times
    # >>> The couple G,s=4 appears 2 times
    # >>> The couple c,mi=6 appears 1 times
    # >>> The couple a,m=2 appears 1 times
    # >>> ...

在csv文件中识别排列（并计算它们）

1 个答案: