我坚持下面的代码3的解决方案。我需要插入一个简单的数学问题,在翻阅我的书并从课堂上观看视频之后我无法想到这一点。我希望程序能够提出这样一个问题:“8的强大之处是什么?”答案为“64”。有谁愿意帮帮我吗?如果有人能让我开始,我可以提出另外两个问题!非常感谢你!!金
import java.util.Scanner; //allows for input
public class ASG03 {
public static void main(String[] args) {
Scanner input = new Scanner(System.in); //allows for input
//Step 1 - Declare and initialize variables
String candidateName = "";
String responseE = "";
int option = 0;
double score = 0;
if (score <=85)
responseE = "Definite";
else if (score <=70)
responseE = "Likely";
else if (score <=60)
responseE = "Maybe";
else
responseE = "No";
String responseI = "";
if (score <=85)
responseI = "Yes";
else if (score <=70)
responseI = "Yes";
else if (score <=60)
responseI = "Yes";
else
responseI = "No";
//Step 2 - Process input
System.out.println("Enter candidate name: ");
candidateName = input.nextLine();
System.out.println("Enter score 0 -100: ");
score = input.nextDouble();
System.out.println();
System.out.println("Enter 1 to set employment category ");
System.out.println("Enter 2 to set interview possibility ");
System.out.println("Enter 3 to view a sample test question ");
System.out.println("Enter option now -> ");
option = input.nextInt();
//Step 3 and 4 - Process calculations and output
switch(option)
{
case 1:
System.out.println("You are now setting the employment category...");
//can use nested if else
System.out.println("Employment category = " + responseE);
break;
case 2:
System.out.println("You are now setting the interview possibilities...");
System.out.println("Interview possibilites = " + responseI);
break;
case 3:
System.out.println("You are now viewing a sample test question...");
//use random and power from Math library
default:
}//end of switch
}//end of main
}//end of class
答案 0 :(得分:2)
当您运行程序时,在main
中您将responseE
始终设置为“确定”。这是因为:
查看代码流程:
double score = 0;
if (score <=85)
responseE = "Definite";
else if (score <=70)
...
...
第一个if
总是被满足,因此它将永远被执行。
此外,即使您在阅读完分数后评估responseE
,也需要再次考虑如何编写条件。请注意score <= 85
然后score <= 70
.. ..
你应该有这样的东西:
在切换之前:
responseE = getResponse(score);
这是方法getResponse
:
private static String getResponse(double score) {
if (score <=85 && score >70)
return "Definite";
else if (score <=70 && score > 60)
return "Likely";
else if (score <=60 && score > 40) //For example..
return "Maybe";
return "No";
}
您想要评估的其他字段>> 后阅读输入内容相同。
答案 1 :(得分:0)
在我给你答案之前,我需要更多信息。看起来代码想要一个随机数生成器,但是在你的问题中你要求8 ^ 2或8 * 8。你想要哪个?我问,因为随机数生成与硬编码数变量有很大不同