Question

好吧，我最近问了一个关于如何populate a Collection with custom data types的问题，但现在我无法弄清楚如何填充一个简单的字符串Collection。也许有人愿意帮助我。

我简化的班级结构：

public class Accommodation
{
    [XmlElement("Attribute")]
    public Collection<string> Categories;        
}

xml看起来像：

<Accommodation Id="f7cfc3a5-5b1b-4941-8d7b-f8a4a71fa530">
  <Categories>
    <Category Id=Time="1abc23"/>
    <Category Id=Time="2abc34"/>
  </Categories>
</Accommodation>

这就是我的linq语句当前的样子（我需要一些帮助：

from x in doc.Descendants("Accommodation")
select new Accommodation()
{
    Categories = new Collection<string>(x.Descendants("Categories").SelectMany(
    categories => categories.Elements("Category").Select(
    (string)x.Element("Categories").Element("Category").Attributes("Id")).ToList()))
}

此致

Answer 1

看起来你想要这个：

doc.Descendants("Accommodation")
   .Select(x => new Accomodation { Categories = 
                  x.Element("Categories")
                   .Elements("Category")
                   .Select(c => (string)c.Attribute("id")).ToList() });

如果Accommodation是XML的根标签，那就更简单了：

var accomodation = new Accomodation
{
    Categories = doc.Root.Element("Categories")
                         .Elements("Category")
                         .Select(c => (string)c.Attribute("id")).ToList()
}

Answer 2

如果有人好奇，我现在就这样解决了。但我确信我的解决方案可能涉及的开销超过必要的开销。

 IEnumerable<Accommodation> temp = 
    (from x in doc.Descendants("Accommodation")
        select new Accommodation()
        {
            Categories = new Collection<string>(
                x.Descendants("Categories").SelectMany(categories 
                    => categories.Elements("Category").Select(category 
                        => category.Attribute("Id").Value ?? "")).ToList())
        }).ToList();

Linq xml to object - 如何填充Collection <string> </string>

2 个答案: