我需要阅读一些xml并填充我的类结构。如果有人能为我提供一些简洁的代码,我会很高兴。
我简化的班级结构:
public class Event
{
[XmlAttribute("Id")]
public string Id { get; set; }
[XmlElement("StartTimes")]
public Collection<StartTime> StartTimeCollection;
}
public class StartTime
{
[XmlAttribute("Time")]
public string Start { get; set; }
[XmlAttribute("Mon")]
public bool Monday { get; set; }
[XmlAttribute("Tue")]
public bool Tuesday { get; set; }
[XmlAttribute("Wed")]
public bool Wednesday { get; set; }
[XmlAttribute("Thu")]
public bool Thursday { get; set; }
[XmlAttribute("Fri")]
public bool Friday { get; set; }
[XmlAttribute("Sat")]
public bool Saturday { get; set; }
[XmlAttribute("Sun")]
public bool Sunday { get; set; }
}
xml看起来像:
<Event Id="f7cfc3a5-5b1b-4941-8d7b-f8a4a71fa530">
<StartTimes>
<StartTime Time="19:00" Mon="false" Tue="false" Wed="false" Thu="false" Fri="true" Sat="false" Son="false"/>
</StartTimes>
</Event>
这就是我的linq语句的样子:
from x in doc.Descendants("Event")
select new Event()
{
Id = x.Attribute("Id").Value,
StartTimeCollection = x.Descendants("StartTimes") ????????? <-- That's the tricky part for me
}
此致
答案 0 :(得分:2)
由于Collection<T>
公开了IList<T>
的{{3}},您可以使用constructor并写一下:
from x in doc.Descendants("Event")
select new Event() {
Id = x.Attribute("Id").Value,
StartTimeCollection = new Collection<StartTime>(
x.Descendants("StartTimes").SelectMany(
startTimes => startTimes.Elements("StartTime").Select(
startTime => new StartTime() {
Start = startTime.Attribute("Time").Value,
Monday = Boolean.Parse(startTime.Attribute("Mon").Value),
Tuesday = Boolean.Parse(startTime.Attribute("Tue").Value),
Wednesday = Boolean.Parse(startTime.Attribute("Wed").Value),
Thursday = Boolean.Parse(startTime.Attribute("Thu").Value),
Friday = Boolean.Parse(startTime.Attribute("Fri").Value),
Saturday = Boolean.Parse(startTime.Attribute("Sat").Value),
Sunday = Boolean.Parse(startTime.Attribute("Son").Value)
})).ToList())
}
请注意,我使用Attribute("Son")
而不是Attribute("Sun")
来初始化Sunday
属性,因为该属性的名称与标记中的属性相同。不过,这可能是一个错字。