Question

在我的libgdx游戏中，我有3D BoundingBoxes和Spheres用于地图和玩家对象。我想计算它们是否相互碰撞，以便正确模拟这些物体的运动。我可以用什么方法来计算这些物体是否碰撞/交叉？

Answer 1

您可以使用以下方法：

public static boolean intersectsWith(BoundingBox boundingBox, Sphere sphere) {
    float dmin = 0;

    Vector3 center = sphere.center;
    Vector3 bmin = boundingBox.getMin();
    Vector3 bmax = boundingBox.getMax();

    if (center.x < bmin.x) {
        dmin += Math.pow(center.x - bmin.x, 2);
    } else if (center.x > bmax.x) {
        dmin += Math.pow(center.x - bmax.x, 2);
    }

    if (center.y < bmin.y) {
        dmin += Math.pow(center.y - bmin.y, 2);
    } else if (center.y > bmax.y) {
        dmin += Math.pow(center.y - bmax.y, 2);
    }

    if (center.z < bmin.z) {
        dmin += Math.pow(center.z - bmin.z, 2);
    } else if (center.z > bmax.z) {
        dmin += Math.pow(center.z - bmax.z, 2);
    }

    return dmin <= Math.pow(sphere.radius, 2);
}

以

为蓝本

箱体 - 球体交叉口测试的一种简单方法吉姆阿沃来自“图形宝石”，学术出版社，1990年

可在此处找到示例C代码：http://www.realtimerendering.com/resources/GraphicsGems/gems/BoxSphere.c

Answer 2

上述答案仅适用于AABB（Axis Aligned Bounding Box）。该方法虽然简洁美观。所以我把它扩展到包括一般边界框。 Bellow是提供与上述相同算法的最小代码。在下面的代码中，边界框由一个中心和3个方向矢量R，S和T指定。每个都代表方框和主边缘的长度。

struct OBBox{
    vector3 center; 
    vector3 S; // representing side s.
    vector3 R;
    vector3 T;
     /* s, r, and t take -1 or +1 representing a corner along side S, R, and T correspondingly. If one of s, r, or t is 0 then middle of corresponding edge of the non-zero side is returned. If 2 of them are 0, then middle of the plane of the corresponding side is returned. */
    vector3 getCorner(int s, int r, int t)
    {
        return center + ( s*S + r*R + t*T)/2.0;
    }

}

public static boolean intersectsWith(OBBox bbox, Sphere sphere){
    float dmin = 0.;

    vector3 center = sphere.center;
    float centerS = center.S;
    float centerR = center.R;
    float centerT = center.T;

    vector3 bminS = bbox.getCorner(-1, 0, 0);
    vector3 bmaxS = bbox.getCorner(1, 0, 0);
    vector3 bminR = bbox.getCorner(0, -1, 0);
    vector3 bmaxR = bbox.getCorner(0, 1, 0);
    vector3 bminT = bbox.getCorner(0, 0, -1);
    vector3 bmaxT = bbox.getCorner(0, 0, 1);

    if(centerS < bminS.S) {
        dmin += (centerS-bminS).(centerS-minS); // . means 3d dot product.
    else if(centerS > bmaxS)
        dmin += (centerS-bmaxS).(centerS-bmaxS);
    }

    if(centerR < bminR.R) {
        dmin += (centerR-bminR).(centerR-minR);
    else if(centerR > bmaxR.R)
        dmin += (centerR-bmaxR).(centerR-bmaxR);
    }

    if(centerT < bminT.T) {
        dmin += (centerT-bminT).(centerT-minT);
    else if(centerT > bmaxT)
        dmin += (centerT-bmaxT).(centerT-bmaxT);
    }

    return dmin <= (sphere.radius).(sphere.radius);
}

libgdx中BoundingBox和Sphere之间的碰撞检测

2 个答案: