Question

以下代码我添加到SQL Server查询中，现在必须在Oracle中执行相同的操作。我需要在视图中进行分组而不是在C＃中进行分组。我收到此错误消息：

ORA-01747无效的user.table.column或列规范。

我如何编写此代码才能在Oracle中运行？

SELECT CTE.FACILITY_KEY, CTE.DATE, CTE.PATIENT_STATUS, COUNT(*) AS [COUNT]
  FROM CTE
  GROUP BY CTE.FACILITY_KEY, CTE.DATE, CTE.PATIENT_STATUS;

在查询开头我在这里有完整的代码：

  CREATE OR REPLACE VIEW DBD_V_CDL_CHANGES AS 
WITH CTE AS
(
SELECT TR.FACILITY_KEY
       , MV.VALUE_CODE
       , CAST(COUNT(*) AS NUMERIC(9, 0)) COUNT
    FROM OPTC.THS_T_TRANSACTIONS1 TR
    JOIN OPTC.THS_M_MENU2 M
      ON M.MENU_ID = TR.MENU_ID
    JOIN OPTC.THS_M_VALUES MV
      ON MV.MENU_ID = TR.MENU_ID_VALUE
    JOIN OPTC.THS_M_VALUES MV2
      ON MV2.MENU_ID = TR.PREVIOUS_MENU_ID_VALUE
    JOIN OGEN.GEN_M_PATIENT_MAST PM
      ON PM.PAT_NUMBER = TR.PAT_NUMBER
   WHERE TR.TR_DATETIME BETWEEN TRUNC(SYSDATE)
                            AND TRUNC(SYSDATE) + 86399 / 86400
     AND TR.EDIT_NO < 0
     AND MV.VALUE_TYPE IS NULL
     AND MV2.VALUE_TYPE IS NULL
     AND MV.VALUE_CODE >= 0
     AND MV2.VALUE_CODE >= 0
     AND M.SUB_SYS_EXT = 'G1'
     AND ABS(MV.VALUE_CODE - MV2.VALUE_CODE) > 1
     AND (PM.DISCHARGE_DATE IS NULL OR PM.DISCHARGE_DATE < SYSDATE)
   GROUP BY TR.FACILITY_KEY, MV.VALUE_CODE)

   SELECT CTE.FACILITY_KEY, CTE.DATE, CTE.PATIENT_STATUS, COUNT(*) AS [COUNT] FROM CTE
  GROUP BY CTE.FACILITY_KEY, CTE.DATE, CTE.PATIENT_STATUS;

Answer 1

我发现您的代码存在一些问题。

首先，您选择以下三列FACILITY_KEY，VALUE_CODE以及CTE中的计数：

SELECT TR.FACILITY_KEY , 
    MV.VALUE_CODE , 
    COUNT(*) as Count -- note there is no need to CAST(COUNT(*) AS NUMERIC(9, 0)) this
FROM OPTC.THS_T_TRANSACTIONS1 TR

但是当您从CTE中选择时，您正在选择未在CTE中返回的列：

with cte as
( 
  -- your query here does not return DATE or PATIENT_STATUS
) 
SELECT CTE.FACILITY_KEY, 
    CTE.DATE, 
    CTE.PATIENT_STATUS, 
    COUNT(*) AS COUNT 
FROM CTE 
GROUP BY CTE.FACILITY_KEY, CTE.DATE, CTE.PATIENT_STATUS;

PATIENT_STATUS和Date来自哪里，因为您没有将其包含在CTE中？因此，当您尝试选择它们时，这些不存在。

我通过在列表中包含未在CTE查询中选择的列来复制错误。

第二个问题是CTE.DATE列。 DATE是保留字，是双引号CTE."DATE"

的地方

Answer 2

... AS [COUNT]，... AS NUMERIC（9,0））不是Oracle语法，永远不会工作。只需删除[]并使用NUMBER而不是NUMERIC。不需要CAST Count（）。 Count（）函数将始终返回数字，例如0-零或某个数字。

这是Oracle中的有效语法：

SELECT deptno, count(*) total_count_by_dept -- no need to cast or AS --
  FROM scott.emp
GROUP BY deptno
/

尽量不要将保留字用作别名的COUNT：

SELECT CTE.FACILITY_KEY, CTE.DATE, CTE.PATIENT_STATUS, COUNT(*) AS total_cnt -- 'AS' is for clarity only, not required
  FROM CTE
 GROUP BY CTE.FACILITY_KEY, CTE.DATE, CTE.PATIENT_STATUS
/

关于查询的Oracle子错误

2 个答案: