我遇到了tablesorter的问题。我将脚本添加到文档的头部,并确保更改我的表的ID,但它不会让我排序。
表格代码:
<table class="table tablesort" id="table1">
<thead>
<tr>
<th>Summoner Name</th>
<th>Role</th>
<th>Type</th>
<th>Level</th>
<th>Division</th>
<th>Comment</th>
<th>Posted</th>
</tr>
</thead>
<tbody>
<?php
$result = mysql_query("SELECT * FROM na");
$time = floor((time()-'time') / 60);
mysql_query("DELETE FROM na WHERE " . -'time'+time()>3600);
while($row = mysql_fetch_array($result))
{
if($_SERVER['REMOTE_ADDR']==$row['ip']){
echo "<script type='text/javascript'>
$('#buttonop').attr('value', 'Delete Your Listing');
$('#buttonopa').attr('href', 'delete.php');
$('#buttonop').removeClass('btn btn-large btn-success').addClass('btnchange');
</script>";
}
$time = floor((time()-$row['time']) / 60);
{
echo "<tr>";
echo "<td>" . $row['summoner'] . "</td>";
echo "<td>" . $row['role'] . "</td>";
echo "<td>" . $row['type'] . "</td>";
echo "<td>" . $row['level'] . "</td>";
echo "<td>" . $row['division'] . "</td>";
echo "<td style='width: 350px;'>" . $row['comment'] . "</td>";
echo "<td>" . $time . " minute(s) ago </td>";
echo "</tr>";
}
}
?>
</tbody>
</table>
分拣机代码:
$(document).ready(function()
{
$("#table1").tablesorter();
}
);
答案 0 :(得分:2)
您在粘贴的第一行上将您的类命名为“tablesort”而不是“tablesorter”。尝试将其更改为“tablesorter”,看看是否有效。