STL String :: length（）SEGFAULTing

Question

#include <iostream>
#include <string>
#include <vector>

/*
  Using STL's string class because the problem does not refer any
  limits regarding the number of characters per line.
 */

using namespace std;

int main()
{
  string line;
  vector<string> lines;
  while (getline(cin, line))
  {
    lines.push_back(line);
  }

  unsigned int i, u;
  unsigned int opening = 1; // 2 if last was opening, 1 if it was closing
  for (i = 0; i < (int) lines.size(); i++)
  {
    for (u = 0; u < (int) lines[u].length(); u++)
    {

    }
  }

  return 0;
}

我有那么简单的代码只读取几行（输入文件）：

"To be or not to be," quoth the Bard, "that
is the question".
The programming contestant replied: "I must disagree.
To `C' or not to `C', that is The Question!"

然而，我发现它是SEGFAULTing，因为它在第一行（第四个字符）上读取一个''（空格）字符：

(gdb) run < texquotes_input.txt 
Starting program: /home/david/src/oni/texquotes < texquotes_input.txt

Program received signal SIGSEGV, Segmentation fault.
0x00007ffff7b92533 in std::string::length() const () from /usr/lib/x86_64-linux-gnu/libstdc++.so.6

我真的不明白为什么，我在循环中没有做任何事情，我只是在循环。

Answer 1

我已经发现了问题。这是内循环：

for (u = 0; u < (int) lines[u].length(); u++)
{

}

应该是：

for (u = 0; u < (int) lines[i].length(); u++)
{

}

Answer 2

在另一个答案中，已经发现了索引错字。

我想补充一点，使用基于范围的for循环这些问题更难以发生，因为循环更加“隐含”：

#include <iostream>
#include <string>
#include <vector>
using namespace std;

int main()
{
  string line;
  vector<string> lines;
  while (getline(cin, line))
  {
    lines.push_back(line);
  }

  for ( const auto& currLine : lines )
  {
    for ( auto ch : currLine )
    {
      cout << ch;  
    }
    cout << '\n';
  }
}