Question

我是java新手，做得不好，需要一些帮助。我有一个名为“RestaurantObject”的类，我正在尝试从我的主要类中创建一个对象。我遇到了问题，因为该对象中的一个变量是一个数组。我真的不确定该把它放在那里。

这是我的主要内容：

public class MyRestaurantObject {
     public static void main(String[] args) {

     RestaurantObject mcDonalds = new RestaurantObject("McDonalds", "McDonalds Menu", **WHAT GOES HERE?**);

以下是我的班级“RestaurantObjects”的代码

public class RestaurantObject {

private static final Object[] String = null;
private String restaurantName;
private String menu;
private String [] employees;


public RestaurantObject(String name, String menu, String [] employees){
setRestaurantName(name);
setMenu(menu);
setEmployees(employees);
}


//restaurantName
public String getRestaurantName(){
return restaurantName;
}

private void setRestaurantName(String name){
restaurantName = name;
}

//menu
public String getMenu(){
return menu;
}

private void setMenu(String menu){
this.menu = menu;
}

//employees
public String[] getEmployees(){
return employees;

}

private void setEmployees(String [] employees){
this.employees = employees;
}

}

我知道我做得不对。请帮忙！

谢谢！

另外，如果我的任何术语有误，请纠正我。

Answer 1

只需在第三个参数中传递一个新的字符串数组。

RestaurantObject mcDonalds = new RestaurantObject("McDonalds", "McDonalds Menu", new String[] {"Value1", "Value2"});

Answer 2

我猜你还没有学过Java varargs，但这是一个使用它们的完美案例。然后你可以去

public RestaurantObject(String name, String menu, String...employees) {
   setRestaurantName(name);
   setMenu(menu);
   setEmployees(employees);
}

以后，

RestaurantObject mcDonalds = new RestaurantObject(
        "McDonalds", "McDonalds Menu", "John Doe", "Jane Doe");

如果您还没有使用或尚未学习varargs，@ fvu版本2是我的首选。

Answer 3

有两种选择：

1在创建RestaurantObject之前创建数组（该类应该只是被称为Restaurant

String[] emplArr = new String[]{ "Bob", "Alice", "Fred"};
RestaurantObject mcDonalds;
mcDonalds = new RestaurantObject("McDonalds", "McDonalds Menu", emplArr);

2在RestaurantObject的构造函数调用中使用静态初始化器初始化数组

RestaurantObject mcDonalds;
mcDonalds = new RestaurantObject("McDonalds", "McDonalds Menu", new String[]{ "Bob", "Alice", "Fred"});

Answer 4

你可以做到

RestaurantObject mcDonalds = new RestaurantObject(
    "McDonalds", "McDonalds Menu", new String[] {"John Doe", "Jane Doe"});

或

String[] employees = new String[] {"John Doe", "Jane Doe"};
RestaurantObject mcDonalds = new RestaurantObject(
    "McDonalds", "McDonalds Menu", employees);

或

String[] employees = new String[2];
employees[0] = "John Doe";
employees[1] = "Jane Doe";
RestaurantObject mcDonalds = new RestaurantObject(
    "McDonalds", "McDonalds Menu", employees);

关于后者的说明：当你创建这样的数组时，你必须知道它的大小，这有时会非常烦人。这就是为什么许多人更喜欢使用ArrayList s，其行为或多或少像弹性数组，即在添加n项时自动扩展。

初始化包含数组的类的新对象

4 个答案: