Question

你好，我的服务有问题。我正在创建一个实现UDPServer的应用程序，并在接收到的数据包中记录主要活动。即使活动已关闭，我希望服务启动，所以我认为我必须使用服务。这是真的吗？我已经意识到一个应用程序实现了一个没有问题的音乐播放器服务，但是当在服务onStart函数中插入UDP服务器的代码我的应用程序粉碎。这是关于udp服务器的代码：

    InetAddress serverAddr = InetAddress.getByName(SERVERIP);       
    //Create the socket using the serverAddress 
    //notifica("STARTING SERVER!", "UDP***Creating server" );
    //System.out.println("UDP***Creating server"); 
    DatagramSocket socket = new DatagramSocket(SERVERPORT, serverAddr); 

    //create a buffer to copy packet contents into 
    byte[] buf = new byte[260]; 
    //create a packet to receive 
    DatagramPacket packet = new DatagramPacket(buf, buf.length); 
    notifica("START!", "Server started!" );
    while(true) {

        try{
            socket.receive(packet); 
            System.out.println("UDP***" + new String(packet.getData())); 
            notifica("RECEIVED!", new String(packet.getData()) );

        } catch (Exception e) { 
        notifica("EXC_INT:", "UDP Received Exception! " + e.toString() );
        }

    }

我认为问题在于命令：

socket.receive(packet);

它会阻止执行并等待读取内容。我希望主程序不会阻止等待服务。

我尝试在服务中插入超时和睡眠命令而没有任何结果：

    InetAddress serverAddr = InetAddress.getByName(SERVERIP);       
    //Create the socket using the serverAddress 
    //notifica("STARTING SERVER!", "UDP***Creating server" );
    //System.out.println("UDP***Creating server"); 
    DatagramSocket socket = new DatagramSocket(SERVERPORT, serverAddr); 

    //create a buffer to copy packet contents into 
    byte[] buf = new byte[260]; 
    //create a packet to receive 
    DatagramPacket packet = new DatagramPacket(buf, buf.length); 
    notifica("START!", "Server started!" );
    while(true) {

        try{
            socket.setSoTimeout( 100 );
            socket.receive(packet); 
            System.out.println("UDP***" + new String(packet.getData())); 
            notifica("RECEIVED!", new String(packet.getData()) );
        } catch (SocketTimeoutException e) { 
        //notifica("EXC:", "UDP No data received!" );
        //Toast.makeText(getApplicationContext(), "UDP No data received!", Toast.LENGTH_SHORT).show();   
        } catch (Exception e) { 
        notifica("EXC_INT:", "UDP Received Exception! " + e.toString() );
        }
        try{
             Thread.sleep(30000);
        } catch (Exception e) { 
             notifica("EXC_INT_TIMER:", "Thread sleep exc! " + e.toString() );
        }
    }

谢谢！

Answer 1

如果您不希望主程序在socket.receive（数据包）上阻塞，则必须实现线程;

这样做的一种方法是将阻止代码放在此处：

new Thread（）{

 public void run(){

//在此处设置阻止代码，例如

while（true）{

    try{
        socket.setSoTimeout( 100 );
        socket.receive(packet); 
        System.out.println("UDP***" + new String(packet.getData())); 
        notifica("RECEIVED!", new String(packet.getData()) );
    } catch (SocketTimeoutException e) { 
    //notifica("EXC:", "UDP No data received!" );
    //Toast.makeText(getApplicationContext(), "UDP No data received!", Toast.LENGTH_SHORT).show();   
    } catch (Exception e) { 
    notifica("EXC_INT:", "UDP Received Exception! " + e.toString() );
    }
    try{
         Thread.sleep(30000);
    } catch (Exception e) { 
         notifica("EXC_INT_TIMER:", "Thread sleep exc! " + e.toString() );
    }
} 

}

}开始（）;

此外，如果您设置超时和睡眠以解决问题，请将其删除，因为它无法解决您的崩溃问题。

服务块eìapplication执行

1 个答案: