Question

您好，对于程序我必须创建3个按钮，并且当鼠标按下每个按钮时颜色必须改变，我很困惑如何在按下鼠标时将按钮切换为不同的颜色使用处理语言，任何提示？到目前为止这是我的代码！

小部件主程序

     PFont stdFont;
     final int EVENT_BUTTON1=1;
   final int EVENT_BUTTON2=2;
   final int EVENT_BUTTON3=3;
   final int EVENT_NULL=0;
   Widget widget1, widget2,widget3;
   ArrayList widgetList;


  void setup(){
  stdFont=loadFont("AbadiMT-CondensedLight-48.vlw");
  textFont(stdFont);

 widget1=new Widget(100, 100, 180, 40,
"RED", color(100),
stdFont, EVENT_BUTTON1);
widget2=new Widget(100, 200, 180, 40,
"GREEN", color(100),
stdFont, EVENT_BUTTON2);                          
size(400, 400);
widget3=new Widget(100, 300, 180, 40,
"BLUE", color(100),
stdFont, EVENT_BUTTON2);                          
size(400, 400);


 widgetList = new ArrayList();
widgetList.add(widget1); widgetList.add(widget2); widgetList.add(widget3);

 }

 void draw(){
  for(int i = 0; i<widgetList.size(); i++){
Widget aWidget = (Widget)widgetList.get(i);
aWidget.draw();
  }

  }

void mousePressed(){
 int event;

  for(int i = 0; i<widgetList.size(); i++){
Widget aWidget = (Widget) widgetList.get(i);
   event = aWidget.getEvent(mouseX,mouseY);
   switch(event) {
     case EVENT_BUTTON1:
       println("button 1!");
       break;
     case EVENT_BUTTON2:
       println("button 2!");
       break;

       case EVENT_BUTTON3:
       println("button 3!");
       break;
   }  
 }
}



main widget class

 class Widget {
 int x, y, width, height;
 String label; int event;
   color widgetColor, labelColor;
 PFont widgetFont;

  Widget(int x,int y, int width, int height, String label,
   color widgetColor, PFont widgetFont, int event){
   this.x=x; this.y=y; this.width = width; this.height= height;
   this.label=label; this.event=event; 
  this.widgetColor=widgetColor; this.widgetFont=widgetFont;
   labelColor= color(0);
  }
 void draw(){
  fill(widgetColor);
  rect(x,y,width,height);
  fill(labelColor);
  text(label, x+10, y+height-10);
}
 int getEvent(int mX, int mY){
 if(mX>x && mX < x+width && mY >y && mY <y+height){
    return event;
 }
 return EVENT_NULL;
}
     }

Answer 1

听起来像是家庭作业。一般答案：

class RectangularThing {
  float x, y, w, h;
  color boxColor = 0;
  [...]
  boolean over(float mx, float my) {
    // return "true" if mx/my is inside this rectangle,
    // otherwise return "false"
  }
  void setColor(color c) {
    boxColor = c;
  }
  void draw() {
    stroke(boxColor);
    fill(boxColor);
    rect(x,y,w,h);
  }
}

[...]

ArrayList<RectangularThing> allmythings;

void setup() {
  ...
  allmythings = new ArrayList<RectangularThing>();
  ...
}

void draw() {
  // this kind of looping is the same as
  // "for(int i=0, last=allmythings;i<last;i++) { 
  //    RectangularThing t = allmythings[i];
  //    ..." except that it's less code and easier
  // to read. If you're just iterating without
  // needing the iteration counter, this is nicer.
  for(RectangularThing t: allmythings) {
    t.draw();
  }
} 

void mouseClicked() {
  for(RectangularThing t: allmythings) {
    if(t.over(mouseX,mouseY)) {
      t.setColor(...);
    }
  }
  redraw();
}

所以：让自己负责绘制自己，并给予他们正确完成所需的所有属性。然后在需要时根据代码或用户交互更改这些属性。

如何使用处理语言按下鼠标来更改颜色

1 个答案: