Question

我认为我的JUnit测试会用语言更好地解释这个问题！

    @Test
public void query8times(){

    for(int i=0; i<15; i++){
        ProspectoRadarQueryBuilder prqb = new ProspectoRadarQueryBuilder("jardeu");
        List<Object[]> prospectosNotas = (List<Object[]>) genericFilterDao.executeSQL(prqb.buildQuery());   
        System.out.println("------------------------------------- "+i);
    }
}

控制台上的结果是：

Hibernate:   SELECT * FROM   (   select         p.id,           comparestrings('jardeu', pc.valor) as nota   from           com_prospecto p         inner join com_prospecto_campo pc ON (p.id = pc.id_prospecto)           inner join com_campo c ON (pc.id_campo = c.id AND c.flag_nome = true)    ) as subQuery   where          nota is not null            AND         nota > 0.35  order by           nota desc;
------------------------------------- 0
Hibernate:   SELECT * FROM   (   select         p.id,           comparestrings('jardeu', pc.valor) as nota   from           com_prospecto p         inner join com_prospecto_campo pc ON (p.id = pc.id_prospecto)           inner join com_campo c ON (pc.id_campo = c.id AND c.flag_nome = true)    ) as subQuery   where          nota is not null            AND         nota > 0.35  order by           nota desc;
------------------------------------- 1
Hibernate:   SELECT * FROM   (   select         p.id,           comparestrings('jardeu', pc.valor) as nota   from           com_prospecto p         inner join com_prospecto_campo pc ON (p.id = pc.id_prospecto)           inner join com_campo c ON (pc.id_campo = c.id AND c.flag_nome = true)    ) as subQuery   where          nota is not null            AND         nota > 0.35  order by           nota desc;
------------------------------------- 2
Hibernate:   SELECT * FROM   (   select         p.id,           comparestrings('jardeu', pc.valor) as nota   from           com_prospecto p         inner join com_prospecto_campo pc ON (p.id = pc.id_prospecto)           inner join com_campo c ON (pc.id_campo = c.id AND c.flag_nome = true)    ) as subQuery   where          nota is not null            AND         nota > 0.35  order by           nota desc;
------------------------------------- 3
Hibernate:   SELECT * FROM   (   select         p.id,           comparestrings('jardeu', pc.valor) as nota   from           com_prospecto p         inner join com_prospecto_campo pc ON (p.id = pc.id_prospecto)           inner join com_campo c ON (pc.id_campo = c.id AND c.flag_nome = true)    ) as subQuery   where          nota is not null            AND         nota > 0.35  order by           nota desc;
------------------------------------- 4
Hibernate:   SELECT * FROM   (   select         p.id,           comparestrings('jardeu', pc.valor) as nota   from           com_prospecto p         inner join com_prospecto_campo pc ON (p.id = pc.id_prospecto)           inner join com_campo c ON (pc.id_campo = c.id AND c.flag_nome = true)    ) as subQuery   where          nota is not null            AND         nota > 0.35  order by           nota desc;
------------------------------------- 5
Hibernate:   SELECT * FROM   (   select         p.id,           comparestrings('jardeu', pc.valor) as nota   from           com_prospecto p         inner join com_prospecto_campo pc ON (p.id = pc.id_prospecto)           inner join com_campo c ON (pc.id_campo = c.id AND c.flag_nome = true)    ) as subQuery   where          nota is not null            AND         nota > 0.35  order by           nota desc;
------------------------------------- 6
Hibernate:   SELECT * FROM   (   select         p.id,           comparestrings('jardeu', pc.valor) as nota   from           com_prospecto p         inner join com_prospecto_campo pc ON (p.id = pc.id_prospecto)           inner join com_campo c ON (pc.id_campo = c.id AND c.flag_nome = true)    ) as subQuery   where          nota is not null            AND         nota > 0.35  order by           nota desc;
------------------------------------- 7

现在让我们看一下源代码！

public List<?> executeSQL(String sql) {
    EntityManager entityManager = entityManagerFactory.createEntityManager();
    entityManager.getTransaction().begin();

    Session hibernateSession = entityManager.unwrap(Session.class);
    Query q = hibernateSession.createSQLQuery(sql);

    return q.list();
}

我用另一个查询做了另一个测试

@Test
public void anotherQuery(){

    for(int i=0; i<15; i++){
        List<Object[]> prospectosNotas = (List<Object[]>) genericFilterDao.executeSQL("select * from com_campo");   
        System.out.println("------------------------------------- "+i);
    }
}

结果如下：

Hibernate: select * from com_campo
------------------------------------- 0
Hibernate: select * from com_campo
------------------------------------- 1
Hibernate: select * from com_campo
------------------------------------- 2
Hibernate: select * from com_campo
------------------------------------- 3
Hibernate: select * from com_campo
------------------------------------- 4
Hibernate: select * from com_campo
------------------------------------- 5
Hibernate: select * from com_campo
------------------------------------- 6
Hibernate: select * from com_campo
------------------------------------- 7

所以，我使用Spring Data ......可能是什么问题？

Answer 1

你不应该只创建一个EntityManager吗？

EntityManager entityManager = entityManagerFactory.createEntityManager();

^行应该在executeSQL方法之外。

Answer 2

是的，正如adarshr所说，我只创建了一个entityManager。但那不是问题。我忘了提交交易并关闭实体经理......

这是最终结果：

 public List<?> executeSQL(String sql) {
    EntityManager entityManager = entityManagerFactory.createEntityManager();
    entityManager.getTransaction().begin();

    Session hibernateSession = entityManager.unwrap(Session.class);
    Query q = hibernateSession.createSQLQuery(sql);

    List<?> list = q.list();

    entityManager.getTransaction().commit();
    entityManager.close();

    return list;
}

Hibernate只执行8次查询

2 个答案: