Question

我有一个数据库表，其中的列名称中包含更多其他列

ColorA
ColorB
Status

此数据库中的数据如下所示。

ColorA     ColorB    Status
---------     ---------    ---------
GREEN           NULL       YES
GREEN           NULL       YES
RED             GREEN      NO
RED             GREEN      YES

我想要的结果是这样的，取决于Status ='YES'

Color  Count
GREEN   3
RED     1

我还定义了包含所有颜色的表。

如何为此构造SQL查询，这将导致前面提到的输出？我有一个查询，但我正在使用LEFT Join然后做一个没有给出正确结果的UNION。

Answer 1

这应该有效：

SELECT a.color, 
       Count(a.color) AS Count 
FROM   (SELECT colora AS color 
        FROM   table1 
        WHERE  status = 'YES' 
               AND colora IS NOT NULL 
        UNION ALL 
        SELECT colorb 
        FROM   table1 
        WHERE  status = 'YES' 
               AND colorb IS NOT NULL) a 
GROUP  BY a.color

<强>结果

| COLOR | COUNT |
-----------------
| GREEN |     3 |
|   RED |     1 |

See the demo

Answer 2

从您给出的示例中，您想知道每个ColorA或ColorB记录的计数

SELECT Color, SUM(Total) AS Count
FROM (
    SELECT ColorA as Color, SUM(CASE WHEN Status = 'Yes' THEN 1 ELSE 0 END) AS Total
    Group By ColorA
UNION
    SELECT ColorB as Color, SUM(CASE WHEN Status = 'Yes' THEN 1 ELSE 0 END) AS Total
    Group By ColorB
) U
GROUP BY Color

Answer 3

这适用于SQL Server，MySQL和PostgreSQL（SQLFiddle demo）：

SELECT color, sum(cnt) AS count FROM (
    SELECT colorA AS color, count(*) AS cnt
    FROM mytable
    WHERE status = 'YES'
    GROUP BY colorA
UNION ALL
    SELECT colorB AS color, count(*) AS cnt
    FROM mytable
    WHERE status = 'YES'
    GROUP BY colorB
) AS x
WHERE color IS NOT NULL  
GROUP BY color

基于2列在SQL Server中具有相同值的值的总和或计数

3 个答案: