Question

我有桌子

+---------------------+
| ID | Code | Amount -|
+---------------------+
| 1  | 101  | 1.2     | 
| 1  | 102  | 1.3     |
| 1  | 103  | 1.3     |
| 1  | 104  | 1.4     |
| 1  | 105  | 1.2     |
| 2  | 101  | 1.5     |
| 2  | 102  | 1.4     |
| 2  | 103  | 1.3     |
| 2  | 104  | 1.1     |
| 2  | 105  | 1.0     |
+---------------------+

我要做的是将每个不是代码101的ID的金额列更改为代码101中的金额值

所以我的输出应该是这样的。

+---------------------+
| ID | Code | Amount -|
+---------------------+
| 1  | 101  | 1.2     | 
| 1  | 102  | 1.2     |
| 1  | 103  | 1.2     |
| 1  | 104  | 1.2     |
| 1  | 105  | 1.2     |
| 2  | 101  | 1.5     |
| 2  | 102  | 1.5     |
| 2  | 103  | 1.5     |
| 2  | 104  | 1.5     |
| 2  | 105  | 1.5     |
+---------------------+

这显然是一个简化的表格，可以显示我需要的东西，因为今天的行数超过100,000，但每天都会改变。

我试过使用游标，但速度很慢。反正有吗？

由于

Answer 1

update t
set t.amount = t2.amount
from your_table t
join 
(
  select id, min(amount) as amont
  from your_table
  where code = 101
  group by id
) t2 on t1.id = t2.id
where t.code <> 101

Answer 2

这样可以解决问题：

DECLARE @t table(ID int, Code int, Amount decimal(6,1))

INSERT @t values
(1,101,1.2),(1,102,1.3),
(1,103,1.3),(1,104,1.4),
(1,105,1.2),(2,101,1.5),
(2,102,1.4),(2,103,1.3),
(2,104,1.1),(2,105,1.0)

;WITH CTE AS
(
  SELECT 
    min(CASE WHEN Code = 101 THEN amount end) 
      over (partition by ID) newAmount,
    Code,
    Amount
  FROM @t
)
UPDATE CTE 
SET Amount = newAmount 
WHERE 
  code <> 101
  AND newAmount is not NULL


SELECT * FROM @t

结果：

ID  Code  Amount
1   101   1.2
1   102   1.2
1   103   1.2
1   104   1.2
1   105   1.2
2   101   1.5
2   102   1.5
2   103   1.5
2   104   1.5
2   105   1.5

Answer 3

您可以像这样使用UPDATE FROM

UPDATE Tbl1
SET Amount = Tbl2.Amount
FROM Tbl1
INNER JOIN
(
SELECT ID,Code,Amount
FROM Tbl1
WHERE Code = 101
)Tbl2
ON Tbl1.ID = Tbl2.ID
WHERE Tbl1.Code <> 101;

修改

如果相同的代码和ID可以有多个金额值，GROUP BY可以像这样使用。

UPDATE Tbl1 SET Amount = Tbl2.Amount FROM Tbl1 INNER JOIN ( SELECT ID,MAX(Amount) as Amount FROM Tbl1 WHERE Code = 101 GROUP BY ID )Tbl2 ON Tbl1.ID = Tbl2.ID WHERE Tbl1.Code <> 101;

Answer 4

example.controller("Ctrl", function($scope) {

  $scope.truck = "Truck Value";                               

});

修改

检查

Update YourTable Set Amount = (select top 1 a.amount from yourtable a where a.id = YourTable.id and a.code = 101)

Answer 5

使用子查询获取id：

的101金额

update tablename t1 set amount = (select max(amount) from tablename t2
                                  where t1.ID = t2.id
                                    and t2.code = 101)
where t1.code <> 101;

无需更新101行，使其不在交易中（where t1.code <> 101）。

MAX(amount)用于确保只从子查询返回一行。

根据同一个表中的另一列更改列值

5 个答案: