Question

现在我有

value = "United states of america"
words_to_ignore = ["the","of"]
new_string = value.split(' ').map {|w| w.capitalize }.join(' ')

我在这里要做的是除了of这个词，我希望其余的大写。因此输出将为United States of America。现在我不确定，怎么做到这一点。

Answer 1

试试这个：

  new_string = value.split(' ')
    .each{|i| i.capitalize! if ! words_to_ignore.include? i }
    .join(' ')

Answer 2

也许尝试类似的事情：

value = "United state of america"
words_to_ignore = ["the","of"]
new_string = value.split(' ').map do |w| 
  unless words_to_ignore.include? w
    w.capitalize
  else
    w
  end
end
new_string[0].capitalize!
new_string = new_string.join(' ')

Answer 3

我建议使用散列将大小写过程和异常存储在一个包中：

value       = 'united states of america'
title_cases = Hash.new {|_,k| k.capitalize }.merge({'of' => 'of', 'off' => 'off'})
new_string  = value.split(" ").map {|w| title_cases[w] }.join(' ') #=> "United States of America"

Answer 4

value = "United state of america"
words_to_ignore = Hash[%w[the of].map{|w| [w, w]}]
new_string = value.gsub(/\w+/){|w| words_to_ignore[w] || w.capitalize}

Answer 5

您可以使用这种方式强制始终使用相同的结果：

downcase_words = ["of", "the"]
your_string.split(' ').each{ |word| (downcase_words.include? word.downcase) ? 
                                     word.downcase! : word.capitalize! }.join(' ')

而your_string可能是：

＆＃39;美国＆＃39;
＆＃39;美利坚合众国＆＃39;
＆＃39; uNitE a stAteS of aMerIca＆＃39;

结果将永远是：＆＃34;美利坚合众国＆＃34;

将每个单词大写，除了数组中的选定单词

5 个答案: